6. From the following data for the first order reaction: C,H,N2 (g) CH(g) + N2 (g),calculate the value of the rate constant k (in s1) by plugging a point intothe rate law.[CH&N2]Rate1.17 x 102 M1.1 x 10-5 M/min1.91 x 1023.83 x 1021.8 x 10-53.6 x 10-5O 1.3 x 107O 45O 66O 9.4 x 104O 3.4 x 107 Will a ppt of PBCO3 (s) form if you mix 20 mL of 1.5 x 108 M Pb(NO3)2(aq) with320 mL of 8.8 x 107 M Na,CO3 (aq)? (Which of the following is entirelycorrect?)OQ = 7.3 x 10 16, no pptOQ = 2.5 x 109, p.ppt formsQ = 1.3 x 10 14, no ppt%3DOQ = 7.3 x 1016, ppt formsO Q = 1.3 x 10 14, ppt forms%3D

1) from the unit of rate constant, it is 1st order kinetics, So, rate law is, Rate = k[C2H6N2]

Answered: 1.17 x 102 M 1.1 x 10-5 M/min 1.91 x…

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1.17 x 102 M 1.1 x 10-5 M/min 1.91 x 102 3.83 x 102 1.8 x 10-5 3.6 x 10-5 O 1.3 x 107 O 45 O 66

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Matter and Measurement

In the universe, there is matter, energy, and void space. The universe contains energy and void space. The definition of matter can be considered as something which possesses mass and consumes space. Chemistry is that branch of science which deals with the study of matter. Under chemistry, nature, composition, and the changes occurring to matter are discussed.

Question

From the following data for the first order reaction: C,H,N2 (g) CH
(g) + N2 (g),
calculate the value of the rate constant k (in s1) by plugging a point into
the rate law.
[CH&N2]
Rate
1.17 x 102 M
1.1 x 10-5 M/min
1.91 x 102
3.83 x 102
1.8 x 10-5
3.6 x 10-5
O 1.3 x 107
O 45
O 66
O 9.4 x 104
O 3.4 x 107

Will a ppt of PBCO3 (s) form if you mix 20 mL of 1.5 x 108 M Pb(NO3)2
(aq) with
320 mL of 8.8 x 107 M Na,CO3 (aq)? (Which of the following is entirely
correct?)
OQ = 7.3 x 10 16, no ppt
OQ = 2.5 x 109, p
.ppt forms
Q = 1.3 x 10 14, no ppt
%3D
OQ = 7.3 x 1016, ppt forms
O Q = 1.3 x 10 14, ppt forms
%3D

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