1. Work and Heat are Path Functions. bteam undergoes the following reversible process in a closed system. Step 1- 2: Starting at initial conditions P1 %3D 10 bar and tı = 400°C steam is heated to t2 = 550°C under constant pressure conditions. %3D Step 2 - 3: Under constant volume conditions, the pressure is decreased to P3 = 8 bar. The steam does not behave as an ideal gas. Steam properties are summarized below: D (m³/kg) Ū (kJ/kg). Ĥ (kJ/kg) State P(bar) t(°C) 3264.4 2957.8 1 10 400 0.3066 3588.1 2 0.3777 3210.4 10 550 3244.3 0.3777 2942.1 389 Calculate Q123 = Q12+ Q23 in (kJ/kg) a. b. Calculate W123 = W12+ W23 in (kJ/kg) Useful conversion 100 kJ/m³ ·bar

Can you explain the set up of how to solve for the mass flow rate of position 3, the flow rate leaving the condenser?  I do not require the entire solution, just the set-up. This is a distillation column problem, and all enthalpies are provided, almost all mass fractions are provided as well, but no flow rates were given.

I need help on these two questions.Thank YOU

help please answer in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all working!