1. When 2.12 grams of benzoic acid, HC6H5CO₂ (ag), is dissolved in 1.2 L of water, the pH is found to be 2.75. Calculate the experimental Ka for benzoic acid. Answer: ICE Table H₂0(1) [HC6H5CO₂ (aq)] Mol/L [C6H5CO₂- (aq)] Mol/L [H30+(aq)] Mol/L I с E 2. If the pH of a 0.139 mol/L HX solution is 2.00, what is the equilibrium constant of the acid? S Answer ICE Table H₂0(1) [H30+ (aq)] [HX (aq)] Mol/L [X-(aq)] Mol/L Mol/L I с

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Can someone please help me with these two questions. I need to know how to input the information into the ice table. Thank you so much

1. When 2.12 grams of benzoic acid, HC6H5CO₂ (ag), is dissolved in 1.2 L of water, the pH is found to be 2.75.
Calculate the experimental Ka for benzoic acid.
Answer:
ICE Table
H₂0(1)
[HC6H5CO₂ (aq)]
Mol/L
[C6H5CO₂- (aq)]
Mol/L
[H30+(aq)]
Mol/L
I
с
E
2. If the pH of a 0.139 mol/L HX solution is 2.00, what is the equilibrium constant of the acid? S
Answer
ICE Table
H₂0(1)
[HX (aq)]
Mol/L
[X-(aq)]
Mol/L
[H30+(aq)]
Mol/L
I
с
E
Transcribed Image Text:1. When 2.12 grams of benzoic acid, HC6H5CO₂ (ag), is dissolved in 1.2 L of water, the pH is found to be 2.75. Calculate the experimental Ka for benzoic acid. Answer: ICE Table H₂0(1) [HC6H5CO₂ (aq)] Mol/L [C6H5CO₂- (aq)] Mol/L [H30+(aq)] Mol/L I с E 2. If the pH of a 0.139 mol/L HX solution is 2.00, what is the equilibrium constant of the acid? S Answer ICE Table H₂0(1) [HX (aq)] Mol/L [X-(aq)] Mol/L [H30+(aq)] Mol/L I с E
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