1. To test the null hypothesis p = Po with a single sample of size n, we require that n * Po * (1 – po) > 10. Our test statistic TS is p – Po po*(1-po) where p is the sample proportion. (a) For a two-tailed test, we may compute ±za/2 = ±InvNorm(a/2,0, 1) and check that the test-statistic falls in a tail. Or we may instead compute P = 2 * normalcdf (|TS|, 0, 0, 1) and check that P< a. Suppose our null hypothesis is p = 0.35, that our sample size n = 1000, and that our sample proportion is p = 0.39. i. If we use a two-tailed test, what is our alternative hypothesis: p + 0.35 ? p< 0.35 ? or p > 0.35 ? ii. What would we conclude if we rejected the null hypothesis with a two-tailed test? iii. Can we reject the null hypothesis at level of significance a = 0.05, using a two-tailed test? iv. Can we reject the null hypothesis at level of significance a 0.01, using a two-tailed test? %3D

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