1. The objective lens of a microscope has a focal length of f1 = 5 cm and 40 cm from the eyepiece. When an object is placed 6 cm from the objective lens (46 cm from the eyepiece), the final image formed is inverted and is 15 times as large as the original object. What is the focal length f2 of the eyepiece?

5. A convex lens forms an image of a soda can. The image is 2 cm tall and appears 8 cm from the lens. The height of the soda can is 10 cm. (a) Include a drawing/ray diagram of this setup, (b) Where is the can located (object distance) and (c) what is the focal point of this lens?

6. An object is placed 8.5 cm in front of a convex (converging) spherical lens. Its image forms 3.9 cm in front of the lens. What is the focal length of the lens? * O 19 cm 9.6 cm 2.7 cm 6.1 cm 口 L

You want to purchase a microscope for doing surgeries, which requires that there is at least 10cm distance between the objective lens and the patient. The objective forms a highly magnified real image of the object at a distance L. You want the image to look 50 times larger. What should be focal lengths of the objective and the eye piece assuming L=200mm

A 1.00-cm-high object is placed 4.30 cm to the left of a converging lens of focal length 8.45 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 188.8 height 26.048 X cm in front of the second lens X cm

8. On one side of a converging lens of focal length 20.9 cm, you position an object of height 3.48 cm somewhere along the principal axis. The resultant image has a height of 8.00 cm. How far from the lens is the object located?     30.0 cm   12.0 cm   42.0 cm   21.0 cm

A transparent photographic slide is placed in front of a converging lens with a focal length of 2.20 cm. An image of the slide is formed 14.5 cm from the slide. (a) How far is the lens from the slide if the image is real? (b) How far is the lens from the slide if the image is virtual? Step 1 (a) The real image case is shown in the ray diagram. or Object 1 Figure 1 + P 14.5 cm P Notice that here p + q = 14.5 cm, or q = 14.5 cm - p. The thin-lens equation, with focal length f = 2.20 cm, gives 1 - p² (14.5 cm)p+ p+q = F Description Image | cm² = 0. Using the quadratic formula to solve the above equation gives two solutions. The smaller solution is p= cm and the larger solution is p = cm cm. Both are valid solutions for the real image case.

Mike holds a magnifying glass (convex lens) 5.00 cm above a sheet of paper. He looks at the writing on the page and notices that it is magnified by a factor of 3.00. What is the focal length of the lens he is using? a 2.00 cm b 4.00 cm c 7.50 cm d 3.75 cm

1. How far from the object should the lens be held?

7. An object is placed 50.0 cm in front of a lens of focal length f = 22.0 cm a. What is the image distance? di = b. If the object height is 5.0 cm, what is the image height?