1. The figure shows the position (x) vs time (t) graph of the motion of a particle. A B A + 2 3 4 t, s (a) Calculate the average velocity between the points A and D. x, m 4 3 0 OA (b) At what point is the instantaneous velocity zero? B 1 C m S D (c) At point D, is the velocity positive or negative? Positive Negative

The displacement and the corresponding time of a moving body at constant acceleration is recorded as follows: Time (s) Displacement (m) From these data, what is the average acceleration of the motion? O 5.5 m/s² O 6.9 m/s² 1 3 2 13.2 O-2.2 m/s² O It is not moving at constant acceleration. O 2.2 m/s2 3 21.2 4 27 5 30.6

A particle moves according to a law of motion s = 2t^3 − 9t^2 + 12t + 1.a. Determine the velocity of the particle when it has acceleration of 2 m/s^2.b. When is the particle moving in a positive direction?

(1) 1.24 1.0+ 0.84 0.6+ 0.4+ 0.2+ 0 0.2 0.4 0.6 0.8 1.0 (A) B A particle moves along the x-axis so that its acceleration a (t) is given by the graph above for all values of t where 0 ≤ t ≤ 1. At time t = 0, the velocity of the particle is. Which of the following statements must be true? D BAM! (E The particle passes through x = 0 for some t between t = 0 and t = 1. The velocity of the particle is 0 for some t between t = 0 and t = 1. The velocity of the particle is negative for all values of t between t = 0 and t = 1. The velocity of the particle is positive for all values of t between t = 0 and t = 1. *** The velocity of the particle is less than for all values of tbetween t = 0 and t = 1. R

A particle moves in one dimension, and its position as a function of time is given by x (2.0 m/s)t + (-3.6 m/s²)e². (a) What is the particle's average velocity from t 0.45 s to t = 0.55 s? (Indicate the direction with the sign of your answer.) m/s (b) What is the particle's average velocity from t = 0.49 s to t = 0.51 s? (Indicate the direction with the sign of your answer.) m/s MacBook Air 888 F1 F2 F3 F4 F5 F6 @ #3 $4 3 4 Q W E R T G

Velocity Problem 1. The position of an object is given as a function of time as x(t) = (3.0 m/s)t + (2.0 m/s2)t2. What is the average velocity of the object between t-0.0s and t = 2.0 SP

What is the average velocity of this displacement time graph.  My answer is 0.0833m/s because I am diving the final displacement of 2 metres by 24 seconds.

The position of a particle moving along the x-axis is given by x = 30 t2- 30 t, where x is in meters and t is in seconds. What is the position of the particle when it achieves its maximum speed in the positive x- direction? O 3m O 5.6 m O 9.8 m O 27 m O 4.2 m

The figure shows the acceleration-versus-time graph of a particle moving along the x-axis. Its initial velocity is vox = 6.00 m/s at to = 0 s. What is the particle's velocity at t = 2.00 s? (Figure 1) 1 of 1 Figure a (m/s²) 4 2- 0 2 4 t(s) Part A Express your answer with the appropriate units. μA ? m 14 S Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Provide Feedback