1. The capacitor in the circuit below has an initial voltage of 10 V across it, i.e., v(0)=10V. The switch SW1 is closed at time t=0. a. Use KCL to show that the governing equation for the voltage v(t) is given by dv RC + v = 5 dt b. Solve this governing equation to find v(t) for t>0. What is the time constant? c. Plot v(t) between 0

A circuit with a battery, 2 resistors, a capacitor, and a switch is built as shown in the figure. The battery has voltage V=24.0V, resistor R1= 5.002, resistor R2= 20.02, and capacitor C=150.00µF. At t=0 the switch S is closed and the capacitor C is initially uncharged. 5. R, a. Find the time constant, t, for charging the capacitor. S b. Find the voltage across the capacitor t=4.20x10³s after the switch is closed.

After being closed for a long time the switch in the RC circuit shown below opens at timet=18 ms. Find iO(t) for t > 0 ms. For full credit include the equations and a plot describing iO(t).Hint: use superposition to find the contributions of each source.

In the circuit shown the initial voltages across the capacitors C, and C₂ are 2V and 4V, respectively. The switch is closed at time t = 0. The total energy dissi- pated (in Joules) in the resistor R until steady state is reached, is t = 0 :4F 592 N 2F