1. It has been reported that the average creditcard debt for college seniors at the college bookstore for a specific college is $11,500. Thestudent council at a large university feels thattheir seniors have a debt much less than this, soit conducts a study of 50 randomly selectedseniors and finds that the average debt is10,900, and the population standard deviationis $2,590. With a a=0.05, is the student councilcorrect?2. The average "moviegoer" sees 8.5 movies ayear. A moviegoer is defined as a person whosees at least one movie in a theater in a 12-month period. A random sample of 29moviegoers from a large university revealed thatthe average number of movies seen per personwas 9.6. The standard deviation is 3.2 movies. Atthe 0.02 level of significance, can it be concludedthat this represents a difference from thenational average?3. The average college student goes through 500disposable cups in a year. To raise environmentalawareness, a student group at a large universityvolunteered to help count how many cups wereused by students on their campus. A randomsample of 30 students' results found that theyused a mean of 676 cups with standard deviationof 400 cups. At a=0.15, is there sufficientevidence to conclude that the mean is greaterthan from 500?

1. The provided information is x¯=10900σ=2590n=50 a. The null and alternative hypothesis…

Answered: 1. It has been reported that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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4. Dougall compared the resting heart rate of average healthy citizens and soldiers suffering from post-traumatic stress disorder (PTSD). The normal resting heart rate for 25 healthy people averages 65 beats per minute (bpm) with a standard deviation of 6 bpm. The average heart rate of 16 people suffering from PTSD was 82 bpm with a standard deviation of 8 bpm. Use a = .05 for a two-tailed test. Does PTSD cause an elevation in resting heart rate? Complete all 4 steps of hypothesis testing.
Imagine my business owns two cars and I have to fill the tanks of both cars every week. One car, the smaller one, takes on average $30 to fill the tank with gas with a standard deviation of $3. The other car, the larger one, takes on average $55 to fill the tank with gas with a standard deviation of $4. 1. What is the average amount my business spends on gas each week for these two cars? Put your answer in blank #1. 2. What is the standard deviation on the amount my business spends on gas for these two cars each week? Show your work on paper and put your answer in blank #2.
1. Rini prefers red M&Ms over any other color. The Mars Company, makers of M&Ms, claims that 20% of all M&Ms are red. Rini plans to remove M&Ms from her bag one at a time until she gets her first red. What is the standard deviation of the number of M&Ms she will remove?
The average McDonald's restaurant generates $3.6 million in sales each year with a standard deviation of 0.9. Trent wants to know if the average sales generated by McDonald's restaurants in Kentucky is different than the worldwide average. He surveys 27 restaurants in Kentucky and finds the following data (in millions of dollars): 4.1, 2.8, 4.4, 4.5, 5.3, 5, 3.7, 2.9, 3.8, 4.8, 3.6, 2.3, 3.7, 2.9, 2.9, 4, 1.1, 5.2, 2.9, 5, 4, 4, 5.9, 3.2, 2.2, 4.3, 3.8 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: [? v] ? v На: ? ? v (So we will be performing a Select an answer test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer v with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. P( ? v ? v = P( ? ♥ ?…
1. A researcher suspects that the actual prevalence of depression among children and adolescents is higher than was previously reported. The previously reported prevalence for depression among children and adolescents was 12.5%, and the researcher conducts a study to test the accuracy of the previously reported prevalence of depression among children and adolescents by recruiting 100 total children or adolescents and tests them for depression using the DSM-5. The researcher determines that the prevalence of depression from the study is 12.9% and the standard deviation was 0.4. What should the researcher’s conclusion be for a 5% significance level? Choose from the following. A) We reject H0 at the 5% level because 10 is greater than 1.96. We do have statistically significant evidence to show the actual prevalence of depression among children and adolescents is above the previously reported prevalence of 12.5%. B) We fail to reject H0 at the 5% because -10 is less than 1.645. We do…
2. The mean IQ of a sample of 1600 children was 99. Is it likely that this was a random sample from a population with mean IQ 100 and standard deviation 15?
4. A medical statistician wants to estimate the average weight loss of people who are on a new diet plan. In a preliminary study, he guesses that the standard deviation of weight loss is about 10 pounds. How large a sample should he take to estimate the mean weight loss to within 2 pounds, with a 90% confidence.
2) A job placement director claims that the average starting salary for nurse is $26000. A sample of 18 nurses has a mean salary of $25620 and a standard deviation of $680. Is there enough evidence to reject the directors claim at a = 5% LOS?
10. In a study conducted to determine the role that sleep disorders play in academic performance, researcher Jane Gaultney conducted a survey of 503 randomly selected students with a known sleep disorder (such as narcolepsy, insomnia, or restless leg syndrome) and found their mean GPA was 2.65 with a standard deviation of 0.87. Similarly, she randomly selected 1342 students with no known sleep disorders, and found their mean GPA to be 2.82 with a standard deviation of 0.83. You may assume that both population GPA's are normally distributed. Use a significance level of 0.05 to test whether the two groups have different mean GPA's. As a follow-up, construct and interpret a 95% confidence interval for the true difference in the mean GPA's of the two groups. What would be the type I and type II errors for this problem?
2. The average gasoline price of one of the major oil companies has been $1.00 per gallon. Because of shortages in production of crude oil, it is believed that there has been a significant increase in the average price. In order to test this belief, we randomly selected a sample of 36 of the company's gas stations and determined that the average price for the stations in the sample was $1.04. Assume that the standard deviation of the population (o) is $0.12. a) State the null and the alternative hypotheses for testing the belief. b) Describe a Type I error and a Type II error for this situation. c) What is the critical value at a = .05? d) what's your What is the t-statistic or z-statistic associated with the above sample results?
3. A local hospital doctor's team reports that the average cost of treatment of heart disease is 800 RO. To see if the average cost of treatment is different at a particular hospital, a researcher selected a random sample of 40 patients and found that the average cost of treatment is 400 RO. The standard deviation of the population is 350 RO. At test the claim of the hospital doctors.
2. Ms. Palac, a sociologist, made a study on the age in years of a woman at the time of her first marriage. She randomly selected a sample of 24 and 21 married women from Village A and Village B, respectively. The following data are the mean and standard deviation for each group: Village A: x = 18.63 and s = 5.54 Village B: x = 24.90 and s = 5.54 Test the hypothesis that the women in Village A get married younger than women in Village B. Use 0.10 significance level. Step 1: Null and Alternative Hypothesis Ho: Ha: Step 2: Level of Significance and appropriate test statistic Step 3: Determine the Critical Region Degrees of Freedom (df): Critical Region: Step 4: Compute the z or t value Computations: Step 5: Decide whether to accept or reject Ho Step 6: Conclusion

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