1. In the circuit below find the expression of the frequency response H and plot the corresponding Bode plot for R1=12, R;=2N and C=1µF. Is it a high pass or a low pass filter? What is the gain in the pass-band? Find the -3dB cut-off frequency using the graph and by computing it. R1 + + Vout V;
1. In the circuit below find the expression of the frequency response H and plot the corresponding Bode plot for R1=12, R;=2N and C=1µF. Is it a high pass or a low pass filter? What is the gain in the pass-band? Find the -3dB cut-off frequency using the graph and by computing it. R1 + + Vout V;
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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For the solution provided, i do not understand, when finding w = infinity,
why do we take into account the imaginary numbers only (R2 /(R1+R2))?
Pls provide the derivation of the formula as shown in the solution
Transcribed Image Text:T8.1 : cutoff frequency
1. In the circuit below find the expression of the frequency response H and plot the
corresponding Bode plot for R1=1N, R2=2N and C=lµF. Is it a high pass or a low pass
filter? What is the gain in the pass-band? Find the -3dB cut-off frequency using the graph
and by computing it.
+
R1
+
Vout
R2
Vị
53kHz
gain 2/3 (or -3.5dB)
high-pass
Answer:
Transcribed Image Text:Voltage divider:
R2
V. = V;-
R1 + R2 +
1
juC
V.(jw)
V:(jw)
jwR2C
H(jw) :=
1+ jw(R1 + R2)C
Hlow
jwR2C
jwR2C
H(jw) =
R2
2
1+ jw(R1 + R2)C
Hhigh
R1+ R2
2
→ 20 log
= -3.5dB
3
Cutoff frequency
1
1
fo =
2т (Ri + R2)С
wo =
= 53kHz
(R1 + R2)C
27 321µF
20dB/decade
-3.5dB
90°
-6.5dB
102
103
104
105
106
102
103
104
105
106
fo = 53kHz
fo:
= 53kHz
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