1. In rabbits, coat color is affected by a series of alleles with a hierarchy of dominance such that C+> C ch >Ch > c. Each allele is dominant over all the alleles listed to its right. C+ codes for full color, Cch codes for chinchilia, Ch codes for himalayan (white with black extremities) and small c codes for albino. A chinchilla rabbit is mated to a himalayan rabbit. Each of these rabbits has one albino parent. What are the phenotypes of the offspring and the probability that each wili be produced? Answer
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- olving Monohybrid Inheritance single gene. crosses. The henotypic traits controlled by a single gene. The problems are to give you practice in problem solving using Mendelian genetics. A dominant gene (W) produces wire-haired texture in dogs; its recessive allele (w) produces smooth hair. A group of heterozygous wire-haired individuals are crossed and their F1 progeny are then test-crossed. Determine the expected genotyplc and phenotypic ratios among the test cross progeny:From DNA to Protein and Inheritance Co-Dominance: In co-dominance, the heterozygous individual exhibits the phenotype for both alleles. We used the ABO blood groups as an example of co-dominance. 8. What potential blood types can be present in the offspring if two type "O" mate with one another? (alams 1) Ilgq xal Ligg 9. What are the potential blood types present in the offspring if two parents with type A blood mate with each other? parents 10. What are the potential blood types for offspring that are produced by a parent that is A+ and one that is AB-? Sgningatlo odi nol om sig gonda borooqxs Post-Lab Questions 1. In the human species, polydactyly (theLet’s look at hair texture. Some people have curly hair, some have straight hair and some express a traitthat is in-between (Incomplete Dominance), or wavy hair. Therefore curly and straight are bothhomozygous and wavy is the expression of the heterozygous condition. Instead of using capital and lowercase letters, we’ll add a prime (`) to the letter. This is because one is not dominant over the other, andthey will both contribute to the phenotype. We can use H to indicate curly hair and H` to indicate straighthair.Given this information, complete the square: Parent Phenotype(appearance) Genotype(alleles) 1 Curly hair HH 2 Straight hair H'H' Do you remember where the alleles of each parent go?Parents: Offspring: Genotypes: Phenotypes: What are the potential phenotypes and genotypes of the offspring?
- 2/7 - <. Hair texture is an incompletely dominant trait in humans. The three phenotypes are curly, wavy and straight. Straight only occurs when both parents have straight hair. Curly hair also tends to follow this pattern. Only two wavy haired parents produce all three phenotypes. Please explain this observation using punnett squares. Curly x Curly straight x straight Wavy x wavyClassical Mendelian Genetics, Incomplete Dominance, Codominance, and Multiple Alleles 1. Complete the table given below regarding the phenotype and genotype ratios in completely dominant traits. R and r represent the dominant and recessive allele, respectively. Type of Cross rrx rr RR x rr Rrx rr Rrx Rr Genotype Ratio Phenotype Ratio RR x Rr RR X RR *How would the genotype ratios be affected if the mode o inheritance in incomplete dominance? Codominance? 2. In dogs, barer trait is controlled by a dominant gene D and the silent trait by the recessive gene d. Normal tail is dependent on a dominant gene M and the screw m. Give the probable genotypes of the parents in the following crosses: Phenotype of parents Phenotypes of progeny Genotypes of parents Barker Barker Silent Silent normal screw normal normal a. silent normal x silent normal b. barker normal x silent normal 0 0 6 2 7 2 8 3 c. barker normal x silent screw 4 5 5 3 d. barker screw x silent normal 6 0 0 0 e. barker screw x…Inheritance of a single gene: 7. A tortoiseshell cat mates with an orange cat: What is the probability of their kitten having all-orange fur? [Choose ] [Choose ] 0.25 What is the probability of their kitten having tortoiseshell coloration? 0.5 0.875 1.0 0.625 What is the probability of their kitten having all-black fur? 0.375 0.33 0.75 What is the probability that their black kitten will be male? [Choose ] What is the probability that their tortoiseshell kitten will be male? [Choose ]
- CO-DOMINANCE/I... % Ø Oll ^ 6- 3. A homozygous red gummy bear is crossed with a homozygous yellow gummy bear (red and yellow mixed together make orange). You predicted that all the offspring will be orange gummy bears. Create a Punnett Square, then explain if your prediction was correct. 13 r y 2 / 3 | - h ? & 71 u * 82 87% i + | © k ( 93 O D § ) 014 Р 11 -½ { [ [ ^ 11 = ¾ 11 8 '{' \. BRCA1 is a bi-allelic gene (let's call the two alleles as C and c) that is inherited on an autosome. The C allele is completely dominant over c, expressing breast cancer as a phenotype. Eye color is determined by two independently assorting bi-allelic genes, B (alleles B and b) and G (alleles G and g), such that the Ballele shows dominant epistasis over the G and g alleles. Brown-eyed individuals have at least one copy of the B allele, green eyed individuals have at least one G allele, while blue eyed individuals have neither B nor G. A blue-eyed person whą is a heterozygote carrier for the BRCA1 gene has 3 children with a brown-eyed person (heterozygote for both B and G genes) who does not have breast cancer. (a) What are the possible genotypes and phenotypes of all their possible children? What are their respective probabilities of being observed (please write all genotype and phenotype probabilities)? (b) What is the probability that all three children will be blue-eyed and not…+ Name Course/Year/Sec LABORATORY EXERCISES IN GENETICS Laboratory Instructor Date Activity Sheet OTHER NON MENDELIAN INHERITANCE 1. In rabbits, coat color is affected by a series of alleles with a hierarchy of dominance such that C+> Ch>Ch> c. Each allele is dominant over all the alleles listed to its right. C+ codes for full color, Ceh codes for chinchilla, Ch codes for himalayan (white with black extremities) and small c codes for albino. A chinchilla rabbit is mated to a himalayan rabbit. Each of these rabbits has one albino parent. What are the phenotypes of the offspring and the probability that each will be produced? Answer 2. The autosomal dominant allele ML specifies a tailless phenotype in cats. This allele is lethal in the homozygous state. A tailless female cat is mated to a tailless male cat. What are the phenotypes of the offspring and the probability that each will be produced? Answer 3. Agouti (A) is wild type and produces alternating bands of pigment on each hair.…
- Multiple Alleles- Blood Types 1. Blood Type is controlled by 3 alleles: What are they? allele is recessive alleles are codominant, and in homozygous condition results in O blood group. 2. and 3. What are the genotypes possible for a person who has: A blood? B blood? O blood? AB blood? 4. A man with type AB blood is married to a woman also with type AB blood. Show the cross. What proportion of their children will have: A blood? B blood? O blood? AB blood? 5. A man has type B blood (genotype I"I") is married to a woman with type O (ii) blood. Show the cross. What proportion of their children will have: 1. A blood? 2. B blood? 3. O blood? 4. AB blood? 6. A woman with type A blood (genotype IAi) is married to a type B person (genotype I®i). Show the cross. What proportion of their children will have: A blood? B blood? O blood? AB blood?Se www.on ican webteMSTUARTL 192 Inheritance AO Multiple Alleles in Blood Groups The four common blood groups of the human 'ABO blood group system' are determined by three alleles: A, B, and o (also represented in some textbooks as: 1ª, 1®, and ¡º or just i). This is expressed equally. They each produce a different functional an example of a multiple allele system for a gene. The ABO enzyme that adds a different, specific sugar to the basic sugar antigens consist of sugars attached to the surface of red blood molecule. The blood group A and B antigens are able to react cells. The alleles code for enzymes (proteins) that join together with antibodies present in the blood from other people and must these sugars. The allele O produces a non-functioning enzyme that is unable to make any changes to the basic antigen (sugar molecule. The other two alleles (A, B) are codominant and are be matched for transfusion. Recessive allele: O produces a non-functioning protein Dominant allele: A…Inheritance of multiple genes: 8. A pure-bred grey cat mates with a pure-bred chocolate cat: a. What are the possible phenotypes of their kittens? b. For each of these phenotypes, what is their probability? black [Choose ] [Choose ] 0.75 gray 0.5 0 1.0 0.25 chocolate [Choose ] lilac [Choose ] cinnamon [Choose ] fawn [Choose ] orange [Choose ] cream [Choose ]