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![**Question:** How much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 N? Express your answer in joules and kilocalories.
**Explanation:** This question involves calculating the work done, which is a principle of physics. Work is computed as the product of force and distance. In this case, the force is 5.00 newtons and the distance is 0.600 meters.
To calculate the work done in joules:
\[ \text{Work (J)} = \text{Force (N)} \times \text{Distance (m)} \]
After calculating the result in joules, convert it to kilocalories:
\[ 1 \text{ Joule} = 0.000239 \text{ kilocalories} \]
No graphs or diagrams are present in the image.](https://content.bartleby.com/qna-images/question/62ae25aa-851a-436e-930c-29288d4b94fc/dc21cdf5-8f6c-4230-a638-4fd6872940ca/tu3p0gk_processed.png)
Transcribed Image Text:**Question:** How much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 N? Express your answer in joules and kilocalories.
**Explanation:** This question involves calculating the work done, which is a principle of physics. Work is computed as the product of force and distance. In this case, the force is 5.00 newtons and the distance is 0.600 meters.
To calculate the work done in joules:
\[ \text{Work (J)} = \text{Force (N)} \times \text{Distance (m)} \]
After calculating the result in joules, convert it to kilocalories:
\[ 1 \text{ Joule} = 0.000239 \text{ kilocalories} \]
No graphs or diagrams are present in the image.
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