1. Given the following find solutions for different cases 3 redundant bits to the 2-bit data-word to make 5-bit code-words • Assume the data-word send is 10. The sender creates the code-word 10101 The code-word is corrupted during transmission, and 11101 is received Explain the strategy used by the receiver to correct the codeword. ● Dataword 00 01 10 11 Codeword 00000 01011 10101 11110
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- The code containing of 8 code words which encrypt the communications zero to 1 1 1 as follows: State the succeeding questions with explanation on the question above: Is it linear? what is its block length, message length, charge and distance? how many mistakes can it detect, and how many situations is it incorrect? ( to reply this question grant the best range of errors that the code can assurance to end up conscious of or correct. for occasion a convenient parity bit can word two errors so we would say this can end up conscious of completely a single error. No calculations of risk are required.6. You have received the following 7+4 bit Hamming encoded messages (the Hamming bits are underlined): (a) 11110001011 (b) 11111010110 Assume the messages have been corrupted by at most single bit errors per symbol. Construct tables with the data and redundancy bits and correct the messages if necessarySuppose a binary message word is to encoded using a repetition code where every bit is to be repeated thrice. Which of the ff received word is free of any error 1. 101 101 101 101 2. 111 001 000 111 3. 111 101 111 000 4. 111 000 111 000
- 5. You have received the following 7+4 bit Hamming encoded message (the Hamming bits are underlined): 10010110001 10101101111 Assume the message has been corrupted by at most single bit errors per symbol. Correct the message if necessary.A 15 bit data word along with parity bits received by the receiver is as follows: 101010 111111 011100 110100. Consider the two-dimensional odd parity error detection mechaniem to find out which bit is received in error? if, any. The bits shown in bold with underline are parity bits. Assume sender divides the data in a group of 5 bits each to calculate the parity bitsGiven are the following codewords for an error control coding scheme data 000 011 100 codeword 00011000 00000111 10101000 . a.What is the minimum Hamming distance? b. What is the coding rate for this scheme? c. what raw data rate would be required if we need a throughput of 6 Mpbs? d. in a different situation, the number of data bits to transfer is 5, and the minimum hamming distance is dmin=5. find the maximum coding rate for this situation
- Manchester encoding guarantees frequent clock synchronization by changing signal values. What is the maximum number of bits which may be encoded without a signal change? (Note: The way this question has been asked. you are not to include the bit which includes a signal change in your count)Computer Network : Suppose 3 blocks of 16 bits need to be sent, using Checksum method proves the following cases: When there is no error When there is a burst error and detected. When there is a burst error and remains undetected Block 1: 1011101110101011 Block 2: 0101000011111010 Block 3: 0111010110101010Q) Consider the use of hamming codes to send 11-bit messages. Specifically, consider 10011011011. First, calculate the hamming code-word for this message. Second, invert one message bit in that Hamming code-word (to represent a 1-bit error) and show how the recipient can use the check bits to correct the inverted bit (that is, perform the error correction)
- Assume bit stream of 1110010 as data, polynomial X²+X as divisor. Using the Cyclic Redundancy Check (CRC) algorithm: a. Show in detail the calculations that need to be done by sender to generate sending bit stream. b. Show in detail the calculations that need to be done by receiver to check if the bit stream is received correctly.A block of bits with n rows and k columns uses horizontal and vertical parity bits for error detection. Suppose that exactly 4 bits are inverted due to transmission errors. Drive a mathematical expression of n and k for the total number of different cases where these 4 error bits will be undetected. Show each important step of your derivation. (Hint: the error bits will be undetected if all the parity bits computed from the block remain unchanged.)Suppose the sender and the receiver agree to use the bit pattern 01111110 to mark the beginning and the end of a frame. 1)The sender has the following bits to send. What does the sender actually send? 011110000111111011101111101 2) The receiver receives the following bits. What're the original data bits (note: this question has nothing to do with the previous question) 01111110111110111110001101111101000011111001111110