1. Figure shows the power consumption of a certain household in 1 day. Calculate: (a) the total energy consumed in kWh, (b) the average power per hour over the total 24 hour period. 1200 W PA 800 W 200 W →t (h) 12 2 4 6 8 10 12 2 4 6 8 10 12 noon
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A: 1) Energy = power × time = 4×2.5 kw × 10×30 h = 3000 kwh
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A: Given: Power consumption of a fluroscent bulb is Pf=23.0WCost of compact bulb is Cfb=11.0$Power of…
Q: I can use Rs=200 ohm in part (a) to calculate part (b)?
A: In part (a) the value of Rs is calculated using Ohm's law. Ohm's law can be given as, V = IR By…
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A: Have a look
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Q: A particular household uses a 1.9 kW heater 1.8 h/day ("on" time), four 100 W lightbulbs 6.0 h/day,…
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Q: 13. An energy-efficient fluorescent lightbulb operating at power P1 = 28 W can produce the same…
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Q: Find tension in AC and W ? B 10 lbs w W = 20 b,. TÁC = 17.32 b W = 18 b,. TÁC = 20.1 b, W = 18.95…
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Q: In the figure ₁ = 2.50 V, 2 = 0.803 V, R₁ = 5.57 Q, R₂ = 2.790, R3 = 4.460, and both batteries are…
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