1. Estimate the volume of the following solids by Riemann sums b) The solid lying above the rectangle R = [0,2] × [0, 4] and below f(x, y) X 2. Choose the Riemann sum such that m = n = 2 and choose the points to be evaluated as the upper right corner of each partial domain.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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1. Estimate the volume of the following solids by Riemann sums
b) The solid lying above the rectangle R = [0,2] × [0, 4] and below f(x, y)
12. Choose the Riemann sum such that m = n = 2 and choose the
points to be evaluated as the upper right corner of each partial domain.
Transcribed Image Text:1. Estimate the volume of the following solids by Riemann sums b) The solid lying above the rectangle R = [0,2] × [0, 4] and below f(x, y) 12. Choose the Riemann sum such that m = n = 2 and choose the points to be evaluated as the upper right corner of each partial domain.
where f(x,y) = 4-x-y²
m h
and v= = { f(x;, y ; ) AA
1=1 1=1
Transcribed Image Text:where f(x,y) = 4-x-y² m h and v= = { f(x;, y ; ) AA 1=1 1=1
Expert Solution
Step 1

What is Riemann Sum:

The area under the graph of a positive function on an interval can be approximated by adding the areas of rectangles whose heights are defined by the curve in single-variable calculus. Typically, the interval was divided into smaller sub-intervals, rectangles were drawn to represent the area under the curve on each of these smaller sub-intervals, and the sum of these areas was used to indicate the area under the curve. This approach can be extended to the three-dimensional counterparts of double Riemann sums and double integrals over rectangles.

Given:

A solid is given that lies below fx,y=4-x-y2 and above the rectangle D=0,2×0,4.

To Determine:

We determine the volume of the solid using upper left corner rule Riemann sum.

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