1. Electrons start from rest and are accelerated east by two plates (parallel to the north/south directions) through a potential difference. They then pass into a second set of parallel plates 1.2 cm long (parallel to the east/west direction). When the electrons leave the second set of plates they are moving at 3.0 x 106 m/s [E 30° N]. You may ignore gravity. (For this question but not in the real world!) Find the potential difference across the first set of plates and the electric field between the second set of plates.

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6 An electron is placed in a constant electric field, E = 2.2 x 10¬1³j a. The electron is given an initial velocity of v = 1.5î m. a. Calculate the acceleration that the electron experiences. %3D b. Calculate the time that it takes for the electron to move 1.0m in the -j direction. c. After the time in part b has elapsed, where is the electron relative to its starting position?

QUESTION 4 An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate. The plates are separated by a distance of 1.39 cm, and the electric field within the capacitor has a magnitude of 1743307 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? (Give your answer in 2 d.p. with scientific notation(i.e. 1.23e-12)} 1 Electric field Electron F + + + + + + + + + +

3. Determine the motion, qualitatively, of a positive particle given the following lines of constant electric potential. Briefly explain why your reasoning regarding the motion of the particle. + of originally LOULET -V-IV IV/7V -3 OV 3V -15V 15V

A dipole with –Q at the origin (0,0) and the +Q at coordinates x= 4.00 cm, y = 3.00 cm is in an Electric field, E = 4.25 V/m directed to the right, +x .   (Q = 0.400 C) Draw and label a figure.

2(a). Define electric field strength.   (b). Two flat parallel metal plates, each of length 12.0 cm, are separated by a distance of 1.5 cm, as shown in Fig 2.1 The space between the plates is a vacuum. The potential difference between the plates is 210V. The electric field may be assumed to be uniform in the region between the plates and zero outside this region. Calculate the magnitude of the electric field strength. Field strength = NC^-1 (c). An electron initially travels parallel to the plates along a line mid-way between the plates as shown in Fig.2.1. The speed of the electron is 5.0 × 10^7 ms^-1. For the electron between the plates. (I). Determine the magnitude and direction of its acceleration.  acceleration=................ms^-1 direction............. [4] (ii). Calculate the time for the electron to travel a horizontal distance equal to the length of the plates. time=......... s[1] (d). Use your answers in (c) to determine whether the electron will hit one of the plates or…

6 An electron is placed in a constant electric field, E = 2.2 x 10-13j . The electron is given an initial velocity of v = 1.5i m a. Calculate the acceleration that the electron experiences. -38.13 MM b. Calculate the time that it takes for the electron to move 1.0m in the -j direction. 7.19s c. After the time in part b has elapsed, where is the electron relative to its starting position? 10.6-1.00 m

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3)An electron with speed 2.15×107 m/s is traveling parallel to a uniform electric field of magnitude 1.15×104 N/C . Part A How far will the electron travel before it stops? Part B How much time will elapse before it returns to its starting point?