1. Deduce the structure of this compound from these spectra. C,H120 IHA = | cortoryl 1715 cm s00 00 00 00 0 00 4 00 1400 Normal Carbon DEPT-135 DEPT-90 12 ppm Positive No peak No peak No peak No peak Positive 16 Positive 26 Negative 28 Positive 49 Positive 213 No peak No peak

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Chapter1: Chemical Foundations
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This compound has the formula C6H12O. Determine the structure of the compound 

1. Deduce the structure of this compound from these spectra.
CGH120
IHA = /
Cortoryl
1715 cm
00 0 00 3000 00
24 200
2000
100
1400
1200
Normal Carbon
DEPT-135
DEPT-90
12 ppm
Positive
No peak
No peak
No peak
No peak
Positive
No peak
16
Positive
26
Negative
28
Positive
49
Positive
213
No peak
1.
Transcribed Image Text:1. Deduce the structure of this compound from these spectra. CGH120 IHA = / Cortoryl 1715 cm 00 0 00 3000 00 24 200 2000 100 1400 1200 Normal Carbon DEPT-135 DEPT-90 12 ppm Positive No peak No peak No peak No peak Positive No peak 16 Positive 26 Negative 28 Positive 49 Positive 213 No peak 1.
34
34
34
26
24
2.0
18
16
14
12
10
0.8
06
04
(nnm)
Transcribed Image Text:34 34 34 26 24 2.0 18 16 14 12 10 0.8 06 04 (nnm)
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