1. Consider the dehydration of the following alcohols using a Stre a circle around the alcohols that will dehydrate according to El mechanism, (b) place a box around the alcohols that will dehydrate according to E2 mechanism, and (c) place a triangle around the alcohols that will dehydrate according to both El and E2 mechanisms. он HO OH

The mechanism for the following reaction occurs in a stepwise fashion. мол + он + но Draw the correct mechanism in the space below. Be sure to add lone pairs and charges to structures as needed. Ö Add/Remove step х он Click and drag to start drawing a structure.

lost on this guy as well Be sure to answer all parts. Determine a stepwise mechanism for the following reaction that illustrates why two substitution products are formed. Explain why 1-bromohex-2-ene reacts rapidly with a wide ph Meme under Sx1 reaction conditions, even though it is a 1° alkyl halide. 1-bromohex-2-ene CH₂OH Part 1: The first step in the reaction proceeds according to which mechanism? CH₂CH₂CH₂CH=CHCH₂ CH₂CH₂CH₂CH=CHCH₂ + CH₂OH Part 2 out of 5 Draw the missing resonance contributor. Check my work OCH₁ CH₂CH₂CH₂CH=CH-CH₂ + Br CH₂CH₂CH₂CH=CHCH₂ CH OCH₂ edit structure... Next part +HBr

4. For each given reaction, indicate the major mechanistic pathway(s) (SN1, SN2, E1, E2). Draw the product(s) expected for each reaction. (you do NOT need to draw the mechanism) (TEA= triethyl amine) Br Nal acetone TEA NaCN DMF

Please clearly explain and draw out the mechanism for this reaction. Thank you 1. NaOH, CH(CH),Br, DMF NH 2 NOH HỌ + NH₂

Draw the intermediate and the product for the transformation below. (You should be able to upload a scanned image of hand-drawn molecules by clicking on the image tab above) 1 Ph Mg Br вк 2. H ₂0 ? A Conc. HCl H₂0 ? B

Rearrangements can occur during the dehydration of 1° alcohols even though no 1° carbocation is formed—that is, a 1,2-shift occurs as the C − OH2+ bond is broken, forming a more stable 2° or 3° carbocation, as shown. Using this information, draw a stepwise mechanism that shows how CH3CH2CH2CH2OH is dehydrated with H2SO4 to form a mixture of CH3CH2CH = CH2 and the cis and trans isomers of CH3CH = CHCH3. We will see another example of this type of rearrangement in Section 18.5C.

Draw the major product of the substitution reaction shown below. Ignore any inorganic byproducts. HBr OH HO

Draw the complete electron pushing mechanism for the following transformation.

Draw all the products of the following reaction.