1. Compute for the value of the acceleration due to gravity of an object at an altitude equal to twice the radius of the Earth? (radius of Earth = 6.4 x 10^6 m)2. Scientists once hypothesized the existence of a planet called Vulcan to explain Mercury’s precession. Vulcan is supposed to be between Mercury and the Sun with a solar distance equal to 2/3 of that of Mercury. What would be its supposed period? 3. What is the period T of a planet which radius is as twice as of Earth when it completes one revolution in 875 days? (Earth radius = 6.38 x 10^5) U!! !!me period of the planels H2. What happens to the radius of the orbit of the pianets if it is farther away frOthe sun?sun?3. What is the meaning of the Kepler's constant in terms of planet's revolutioaround the sun?Activity 3: Let's SolveDirections: Solve the following problems1. Compute for the value of the acceleration due to gravity g of an object at analtitude equal to twice the radius of the Earth? (radius of Earth = 6.4 x 10° m2. Scientisis once hypothesized the existence of a planet called Vuican toexplain Mercury's precession. Vulcan is supposed to be between Mercury andthe Sun with a solar distance equal to 2/3 of that of Mercury. WVhat would be%3Dits supposed period?3. What is the period T of a planet which radius is as twice as of Earth when itcompletes one revolution in 875 days? (Earth radius = 6.38 x 105)OTE: Practice

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Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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1. Compute for the value of the acceleration due to gravity of an object at an altitude equal to twice the radius of the Earth? (radius of Earth = 6.4 x 10^6 m)

2. Scientists once hypothesized the existence of a planet called Vulcan to explain Mercury’s precession. Vulcan is supposed to be between Mercury and the Sun with a solar distance equal to 2/3 of that of Mercury. What would be its supposed period?

3. What is the period T of a planet which radius is as twice as of Earth when it completes one revolution in 875 days? (Earth radius = 6.38 x 10^5)

U!! !!me period of the planels H
2. What happens to the radius of the orbit of the pianets if it is farther away frO
the sun?
sun?
3. What is the meaning of the Kepler's constant in terms of planet's revolutio
around the sun?
Activity 3: Let's Solve
Directions: Solve the following problems
1. Compute for the value of the acceleration due to gravity g of an object at an
altitude equal to twice the radius of the Earth? (radius of Earth = 6.4 x 10° m
2. Scientisis once hypothesized the existence of a planet called Vuican to
explain Mercury's precession. Vulcan is supposed to be between Mercury and
the Sun with a solar distance equal to 2/3 of that of Mercury. WVhat would be
%3D
its supposed period?
3. What is the period T of a planet which radius is as twice as of Earth when it
completes one revolution in 875 days? (Earth radius = 6.38 x 105)
OTE: Practice

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