1. Calculate net electric field at the location of point P by all 4 point charges. Also find the totalpotential energy of the system of 4 charges.94 =-6nc• (10 m, 10 m)Point (P)10 m91 2nc92=-4nc93 = 4nc(10 m, 0)(-10 m, 0)(0, 0)

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Answered: 1. Calculate net electric field at the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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8:10 O M „. 6.00 :4l 21 KB/S Imssb1.mutah.edu.jo/m 61 Not yet answered Marked out of 6 P Flag question Find the electric potential energy ( in units of J) stored in a system composed of two point charges q1=11 Uc and 92=17.8 Uc when separated by a distance of 3.5 mm between them. Select one: А. 503.5 B. 111.9 C. 92.3 D. 307.7 Е. 190.2 +
2) Three charges are arranged in the pattern shown. They have equal magnitudes of 1nC but have the signs shown. Three locations, labeled X, Y, and Z, are highlighted. ΟΥ 3 m ox 1 + -4.5E-9 J -3.4E-9 J 0 2 OZ 4 m 4 m i. The electric potential energy stored by this arrangement of charges (using the standard reference point) is A. B. C. D. 1.1E-18 J E. 5.6E-9 J ii. The electric potential at point Y (using the standard reference point) is A. 0.60 V 3 + B. 1.8 V C. 3.0 V D. 6.6 V E. 9.0 V iii. The electric potential at point X (using the standard reference point) is A. 0.15 V B. 2.2 V C. 3.0 V D. 6.6 V E. 9.0 V
2. Three point-like charges are placed at the corners of a rectangle as shown in the figure, a = 28.0 cm and b What is the electric potential energy of the charge 92? 91 = -32.0 μC, 92 = –22.0 μC, 93 = J ssfoss sf60 ssf60 ssf60 ssf60 ssf60 92 soojas de ojas (jss Brojs8 09J800955198 09 +45.0 μC. ssf60 s** ssfóssissf60) 2160 48.0 cm. 0 s60 ssf60 ssf60 ssf60 ssf60 ssf60 s ssf60 ssf60 ssf60 ssf60 f60 ssf
15 - Two particles with 2µC charges and a paticle with charge q=-4x10* C at the origin are given as in the figure. What is the electric potential at the origin due to the two 2µC particles? NOTE: k=9x10°Nm²/C? 2.00 µC 2.00 C x= 0.800 m x= 0.800 m a) 4,5 x 10V 5.5 x 10- V c) 5.6 x 104 V d) 2.5 x 10- V e) 3.0 x 10 V Boş bırak
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1 - A charge q, = 2x10-6 C is located at the origin, and a charge q2 = -6x106 C is located at (0, 3) m, as shown in Figure. What is the total electric potential due to these charges at the point P, whose coordinates are (4, 0) m? -6.00 µC. 3.00 m 2.00 µC 4.00 m a) O 6.29 x 10³ v b) O -6.29 x 10³ V c) O 6.89 x 10³ V d) O -6.89 x 103 v e) O 6x 103 v
8. How much work must be done to move charge Q2 = 2.0 x 10-6 C from A to B? The other charged object has a charge O = 8.0 x 106 C. -5.0 m- -2.0 m- A Q1 = 8.0 x 10-6 C Q2 = 2.0 x 10-6 C %3D (ans: 8.2 x 103 J) Page 3 of 17 2020-12-11
4) The electric field in a certain region is given by the expression E = 4x3 i (N / C). What is the potential difference (V2 - V1 ) between the points x1 = 1 m and x2 = 2 m on the x-axis?
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3) Point charges q, L = 2 m has a total charge q =100 µC and a uniform linear charge density 2 = 50 µC/m in Figure 2. (a) Find the potential at P in Figure 1. (b) Find the total potential energy of charge system in Figure 1. (c) Find the total potential at P in Figure 2. (k = 9×109 N×m²/C², and µ= 10-6) 30 μC, q--20 μC , and q 10 µC are located in Figure 1. A rod with length λ-50 μC/m Qι-30 μC 91 = 30 μC 1 + L = 2 m %3D 0.3 m 0.5 m 4-10 μC 0.3 m + 0.2 m - 0.2 m --> 0.2 m 0.2 m 0.3 m 0.3 m ´0.5 m 92 = -20 µC q2 = -20 µC -1 Figure 1 Figure 2 q- 100 μC

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1. Calculate net electric field at the location of point P by all 4 point charges. Also find the total potential energy of the system of 4 charges. 44 =-6nc (10 m, 10 m) Point (P) 10 m 4 2 nc 92 =-4nc 93= 4nc (10 m, 0) (-10 m, 0) (0, 0)