1. Basin area = 2. Precipitation = 3. Annual precipitation amount converted to m³/yr is 4. Annual discharge is x 108 m³ /yr. 5. Annual storage change AS = 0 (no change) -Water balance equation can be written as P = E + Q + AS/At x106 m² m/yr x108 m³/yr -1. Plug the value into the equation, the annual evaporation from the basin is 2. Convert this to the average evaporation rate in the basin in mm/yr is x106m³/yr mm/yr

icon
Related questions
Question
Either solve whole question or don't solve at all... Vll upvote
A small drainage basin has an area of 5.1 km² and received 380 mm of precipitation in a given year. In the same year, the
stream draining this basin had an average discharge of 1.0 x 106 m³ /yr. Assume that there has been no change in water
stored within the basin. Compute the annual evaporation from the basin in m³ /yr
. Convert everything to standard unit:
x108 m²
1. Basin area =
2. Precipitation =
m/yr
3. Annual precipitation
amount converted to m³/yr is
4. Annual discharge is
x 106 m³ /yr.
5. Annual storage change AS = 0 (no change)
Water balance equation can be written as P = E + Q + AS/At
x106 m³/yr
. 1. Plug the value into the equation, the annual evaporation from the basin is
2. Convert this to the average evaporation rate in the basin in mm/yr is
x106m³/yr
mm/yr
Transcribed Image Text:A small drainage basin has an area of 5.1 km² and received 380 mm of precipitation in a given year. In the same year, the stream draining this basin had an average discharge of 1.0 x 106 m³ /yr. Assume that there has been no change in water stored within the basin. Compute the annual evaporation from the basin in m³ /yr . Convert everything to standard unit: x108 m² 1. Basin area = 2. Precipitation = m/yr 3. Annual precipitation amount converted to m³/yr is 4. Annual discharge is x 106 m³ /yr. 5. Annual storage change AS = 0 (no change) Water balance equation can be written as P = E + Q + AS/At x106 m³/yr . 1. Plug the value into the equation, the annual evaporation from the basin is 2. Convert this to the average evaporation rate in the basin in mm/yr is x106m³/yr mm/yr
Expert Solution
steps

Step by step

Solved in 3 steps with 1 images

Blurred answer