1. At room temperature (25° C), 12.0 mol of SO3 is placed into a 3.0- liter rigid container, and it dissociates by the reaction below: 2503(g) 2502(g) + O2(g) At equilibrium, 9.0 mol of SO3 remains. Answer the following: a.) What is the equilibrium expression Ke? b.) Calculate the equilibrium constant at this temperature. c.) Convert the Ke into Kp. d.) Which reaction is favored at this temperature? e.) Calculate the value of Q if the following initial amounts are placed in the same container and same temperature: 2.0 mol SO3, 3.0 mol SO2, and 4.0 mol O2. What will be the shift of the reaction?

Please help with showing the step and explaining the result with answer, thank you

In the glucose molecule, why is the oxygen at carbon 5 the one that reacts with carbon 1 when there is an additional carbon at the end of the chain, carbon 6? t Predictions: On a. Due to the chirality of the last carbon, carbon 6 b. Because carbon 5 is the last chiral carbon 4 C. Because the oxygen at carbon 5 is in alpha position just like the oxygen at carbon 1 Accessibility: Good to go O 8: 14 101 f5 % 5 f6 A 17 40 & 7 18 Ö 7 W f9 8 8 f10 9 19 11 F ) O n f12 81°F Cla

could you check , both answers are wrong