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Transcribed Image Text:1. An alpha-particle (m = 6.64-10-27 kg; q = 3.2.10-19 C) travels in a circular path of radius 30 cm in a
uniform magnetic field of magnitude 1.8 T.
(a) What is the speed of the particle?
m/s
V=
(b) What is the kinetic energy in electron-volts?
KE=
eV
(c) Through what potential difference must the particle be accelerated in order to give it this kinetic
energy?
V=
V
Hint: What is the relationship between electric potential energy and electric potential? What is the
relationship between the change in kinetic energy and the change in the potential energy of the
alpha particle?
0
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