1. Add the correct type of curved arrow(s) to each reaction below. Draw in lone pairs if needed. Hint: the curved arrow(s) go on the reactant side of the reaction. 2 он A) B) C) HO-OH - Br D) Br-Br E) F) H + Br H Br + Br N + H-Br

Draw the mechanism using curved arrows to show how the electron pairs move for the second step of the given reaction. Include lone pairs and formal charges (if applicable) on the structures. 2m H 哎 1-04 H + H₂O: "X" + HO: + H H

Don't use hand raiting please

I got step two wrong

2. a) Draw mechanism arrows to show how the reactants are converted to the products. b) Using the pKa values in Table 6.1, determine which side of the equilibrium will be favored. H-CI CląC Cl3C HO, H EH H E

Click on a basic (nucleophilic) atom. HH | | H-C-C=C₂ | H H H H-CI:

4 -5 Draw the structure of the product that forms when the carbonyl compound shown is treated with K₂Cr₂O₂. If no reaction occurs, draw the structure of the organic starting material (reactant). COCH₂CH₂ Click and drag to start drawing a structure. 0 :0

Consider the SN2 reaction between 1-bromo-2-methylpropane and methoxide. Add curved arrows to the starting materials to indicate the flow of electrons. Draw the product species to show the balanced equation, including nonbonding electrons and formal charges. H3C. C CH3 Draw curved arrows. H₂C H₂ C. / ||| ||| Select Draw Templates More Br: + :0 -CH3 CH₂ с Br O IU Br : 0 J Erase CH3 product Draw the products. The bromide ion has been drawn for you. Select Draw Templates More Br Erase

Need to check answer 1.Borane (BH3) adds to alkenes to form an alkylborane. In the first box draw the mechanism arrows, and in the second box draw the correct product. Be sure to add lone pairs of electrons and nonzero formal charges to all species.

Don't use hand raiting please