1. A wire carrying a 40-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences a 2.42-N force on the 4.3 cm of wire in the field. What is the average magnetic field strength? Things to Prepare: 1. Draw a sketch of the scenario in your notebook. Draw a vector respresenting the average magnetic field generated by the strong magnet. As no other information is given, the vector can be drawn in any diretion. Draw the current-carrying wire with respect to the field vector drawn above, making sure that it is perpendicular to the field. B= T

1. .A straight wire with length L carries a current I which is directed to the right and is perpendicular to an unknown uniform magnetic field B. A magnetic force F acts on a conductor which is directed downwards. A. Determine the magnitude and the direction of the magnetic field in the region through which the current passes. B. If the angle between the current and the magnetic field is e this time, what would be the new value of the magnitude of the new magnetic force? Pointing System for No. 1: • What are the given in the problem? • What are the unknown variables? • What are the equations that you are going to use? • Solution and answer for Part A. Solution and answer for Part B. L (cm) = 2306 | (A) = 13 F (pN) = 24 O = 61

You have learned that a charge moving in an magnetic field can experience a magnetic force.  Remarkably, anytime that a charged particle moves that particle produces its own magnetic field! The image below of magnetic compasses forming a circle around a current-carrying wire demonstrates the shape of the magnetic field.  The magnetic field lines forms concentric circles around that wire. The strength of the field decreases with increasing distance away from the wire. If the current in the wire is 2.87A, what is the magnitude of the magnitude of the magnetic field (in μT, or micro-Tesla) a distance of 0.43m away from the wire?

1. In the diagram below, a charged particle enters a region of uniform magnètic field where B 0.6 T. The particle has an initial speed of 2.7 x 106 m/s. Keep in mind Newton's Second Law and recall the equation for centripetal acceleration: 1²/r. a. Ignore gravity and first determine the sign of the charged particle if it follows the trajectory of the dashed semicircle. b. Next, use the information given to derive an equation for the charge-to-mass ratio (q/m) of the particle in terms of the particle's speed, the magnitude of the magnetic field and the radius of the semicircle. c. Lastly, calculate the charge to mass ratio of this particle. 95.0 cm B