Answer Q1, 2 & 3 showing clearly all steps 1. A translation of y=f(x) through 2 units parallel to the x-axis is represented byA. y=f(x) + 2B. y=f(x) – 2 C. y = f(x + 2) D. y = f(x - 2)%3D2. A translation of the graph of y = f(x) 2units parallel to the y-axis is the graph of:A. y= f(x) + 2 B. y = f(x) - 2C. y = f(x+2) D. y = f(x-2)3. A reflection of the graph of y = x2 – x – 1 in the x-axis is the graph of2|A. y = x- x - 2 B. y = x² - x – 3 C. y = x- x - 3 D. y = 3 – x – x|4. The reflection of the graph of y = x² + x - 3 in the y-axis is the graph of:2A. y =x+x - 4B. y = x² – x- 3 C. y = x-x- 3 D. y = 3 – x –x²5. y= 2 - x is aA. translation of y = x – 2 through – 1 unit parallel to the x-axisB. reflection of y=x - 2 in the y-axisC. stretch with scale factor -1 parallel to y-axisD. stretch with scale factor -1 parallel to x-axis6. The graph of y = x-x + 5 is first reflected in the y-axis and then translated 3 unitsparallel to the x-axis. The equation of the curve obtained is:A. y = x + x + 8 B. y= -x+ 7x - 17 C. y = x+ 7x + 17D. y= x- 5x + 11%3D%3D27. If the graph of y = x is stretched parallel to the y-axis by scale factor 3 to obtain the%3Dgraph of y= g(x) the g(x) =X2A. 9x B. 3x C. x² + 3 D8. Given that f(x) = f(x-1)2 and that the point (2, 1) on the curve y f(x) corresponds to thepoint (a, b) on the graph of y D(2x) ihe values of a and b are:A. a = 1, b = 2 B. a = 1, b=0 C. a 4, b = 9 D. a = 4, b 3%3D29. The transformation given to y = x2 to obtainis a stretch with scale factor:y :A. ½ parallel to x-axis B. ½ parallel to y-axisC. 2 parallel to x-axis D. 2 parallel to y-axis

Name: Answer Q1, 2 & 3 showing clearly all steps 1. A translation of y=f(x)
Uploaded: 2024-03-20T06:38:44.000Z
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Description: Answer Q1, 2 & 3 showing clearly all steps 1. A translation of y=f(x) through 2 units parallel to the x-axis is represented byA. y=f(x) + 2B. y=f(x) – 2 C. y = f(x + 2) D. y = f(x - 2)%3D2. A translation of the graph of y = f(x) 2units parallel to th