1. A solution containing 50% KOH is fed at a rate of 1000 mol/h to an evaporator to produce a concentrated solution containing 80%mol KOH. The concentrated solution is then fed to a crystallizer to produce a filter cake containing 90% pure KOH and 10% mother liquor (60% KOH solution). The rest of the mother liquor (60% KOH solution) is recycled back to the evaporator. Determine the values of B, C, P and W. Refer to the figure below. H,0 TW F-1000 mole/ B, 8O% KOH P, S0% pure KOH filter 50% by mole KOH 10% (s0s KOH solution) 60% KOH

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter13: The Chemistry Of Solutes And Solutions
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1. A solution containing 50% KOH is fed at a rate of 1000 mol/h to an evaporator to produce a
concentrated solution containing 80%mol KOH. The concentrated solution is then fed to a
crystallizer to produce a filter cake containing 90% pure KOH and 10% mother liquor (60% KOH
solution). The rest of the mother liquor (60% KOH solution) is recycled back to the evaporator.
Determine the values of B, C, P and W. Refer to the figure below.
H,0 TW
P, 9O% pure KOH filter
10% (s0% KOH solution)
F-100X0 mole/hr
B, 80% KOH
50% by mole KOH
60% KOH
Transcribed Image Text:1. A solution containing 50% KOH is fed at a rate of 1000 mol/h to an evaporator to produce a concentrated solution containing 80%mol KOH. The concentrated solution is then fed to a crystallizer to produce a filter cake containing 90% pure KOH and 10% mother liquor (60% KOH solution). The rest of the mother liquor (60% KOH solution) is recycled back to the evaporator. Determine the values of B, C, P and W. Refer to the figure below. H,0 TW P, 9O% pure KOH filter 10% (s0% KOH solution) F-100X0 mole/hr B, 80% KOH 50% by mole KOH 60% KOH
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