1. A small object is 25.0 cm from a bi-concave diverging lens, a second biconvex lens with focal length of 12.0 cm is 30 cm to the right of the diverging lens. The two lens systems form a real inverted image 17cm to the right of the converging lens. What is the focal length of the diverging lens? What is the magnification of the object once it passes through the diverging lens?

An object that is 2.0 cm tall is located 5.0 cm behind the vertex of a converging lens with a focal length of 10 cm as shown in the diagram below. Which of the lettered choices below gives the correct image characteristics? Specifically, what willI be the height, orientation, and nature of the final image? 10 cm Object İ50 5.0 cm f Converging Lens a. 3.0 cm, inverted, real b.4.0 cm, upright, virtual c. 5.0 cm, upright, real d. 4.0 cm, inverted, virtual e. 2.5 cm, upright, virtual O O O O O

A bug is 3 cm to the left of a lens with f = -4.56 cm. Find the image distance from the lens. A second lens of f = 8 cm is placed 1.21 cm to the right of the first lens. Find the distance of the final image from the second lens. Use the image from the first lens as an "object" for the second lens. The final image is: A. Upright B. Inverted   The final image is: A. Real B. Virtual

1. You are trying to photograph a bird sitting on a tree branch, but a tall hedge is blocking your view. However, as the drawing shows, a plane mirror reflects light from the bird into your camera. If x = 3.3 m and y = 4.9 m in the drawing, for what distance must you set the focus of the camera lens in order to snap a sharp picture of the bird's image? oof19 oo 2.1 m 19 0of19 0of19 o0f19 oof19 19 0of19 0of19.

Needs Complete typed solution with 100 % accuracy.

A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 8.30 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position height cm cm -Select- -Select- Is the image real or virtual? O real O virtual in front of the second lens behind the second lens Is the image inverted or upright? O upright O inverted 4

An object is placed 20 cm to the left of a converging lens of focal length 30 cm. A diverging lens of focal length 15 cm is 25 cm to the right of the converging lens. Find the position and magnification of the final image. Object f₁ 42

1. If a lens is to focus parallel light rays on a screen 50-cm away, what diopter would it have? Explain.

1. Why can the object not be focussed if it is any closer to the lens then the near point?   2. When a near object is in focus, where do the parallel rays from the distant object converge relative to the retina? Why?

A person has a far point of 321.0 cm and a near point of 65.4 cm. Bifocals were designed for them to sit 1.78 cm in front of their eyes so that distant objects (d0 = ∞) can be seen clearly with the major lens and a minor lens is formed inside that allows the “focused” eye to read objects at the normal near point (25 cm). 1.What is the power of the major and minor lens in diopters? 2.What would the new near point be if we only looked through the major lens? 3.What would the far point be if we only looked through the minor lens? 4.If you were to construct a telescope from these 2 lenses, assuming a relaxed eye, which lens would be the objective and which the eyepiece, what would be the separation distance between your lenses and what would be the magnification of your telescope?