1. A random sample of 49 business establishments shows that the average monthly water consumption is 35 cubic meters with a standard deviation of 5 cubic meter. Test the hypothesis that the average monthly water consumption is 34 cubic meters at 1% level of significance.
1. A random sample of 49 business establishments shows that the average monthly water consumption is 35 cubic meters with a standard deviation of 5 cubic meter. Test the hypothesis that the average monthly water consumption is 34 cubic meters at 1% level of significance.
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.6: Rational Functions
Problem 11SC: Find the mean hourly cost when the cell phone described above is used for 240 minutes.
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answer the following question with complete solution, graph and answer just like in the example given
![1. A random sample of 49 business establishments shows that the average
monthly water consumption is 35 cubic meters with a standard
deviation of 5 cubic meter. Test the hypothesis that the average
monthly water consumption is 34 cubic meters at 1% level of
significance.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabb4ad0e-49ec-41ce-9614-d43ed644b736%2Ff2b3b90c-a75b-4cd3-be84-14e9d6f5122f%2Fwckmung_processed.png&w=3840&q=75)
Transcribed Image Text:1. A random sample of 49 business establishments shows that the average
monthly water consumption is 35 cubic meters with a standard
deviation of 5 cubic meter. Test the hypothesis that the average
monthly water consumption is 34 cubic meters at 1% level of
significance.
![Solution:
It is a one-tailed test since the alternative hypothesis uses the symbol
for greater than (>). And since o is known and n 2 30, we will use z-test. The
level of significance is 0.05.
From Table 1, the z-critical value is 1.645.
Thus, we have:
71.5 – 70
1.5
z =
8
0.8
V100
z = 1.875
1.645
z-critical value
The computed z-value is 1.875 which is greater than the critical
value of 1.645. Therefore, we reject the null hypothesis and support and
accept the alternative hypothesis that the population mean is greater
than 70.
Example 2:
Consider the following given information. Use a = 0.01. Interpret the result.
Null Hypothesis
Alternative Hypothesis
I = 124.5
Ho: µ = 127
Ha: μ < 127
µ = 127
n = 12
s = 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabb4ad0e-49ec-41ce-9614-d43ed644b736%2Ff2b3b90c-a75b-4cd3-be84-14e9d6f5122f%2F7v2bne9_processed.png&w=3840&q=75)
Transcribed Image Text:Solution:
It is a one-tailed test since the alternative hypothesis uses the symbol
for greater than (>). And since o is known and n 2 30, we will use z-test. The
level of significance is 0.05.
From Table 1, the z-critical value is 1.645.
Thus, we have:
71.5 – 70
1.5
z =
8
0.8
V100
z = 1.875
1.645
z-critical value
The computed z-value is 1.875 which is greater than the critical
value of 1.645. Therefore, we reject the null hypothesis and support and
accept the alternative hypothesis that the population mean is greater
than 70.
Example 2:
Consider the following given information. Use a = 0.01. Interpret the result.
Null Hypothesis
Alternative Hypothesis
I = 124.5
Ho: µ = 127
Ha: μ < 127
µ = 127
n = 12
s = 5
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