Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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The power output is (75 x103) = (0.79)(75 x 10) W 326 And so (0.79 )(75 x 103 Nmax = = 97.53% (0.79)(75 x 10')+750+750 138 Assessment Task 6 1. A quantity is expressed in per unit if it is divided by a chosen base quantity having the same physical dimension). Suppose that for a 10-kVA, 2400-V/240-V transformer we choose P_(base )=10kW v_[1 base )=2400v v_(2 base )=240V This transformer has the following test data open-circuit test (on low-voltage side): short-circuit test (on high-voltage side): Convert all test data into per-unit values and find the series equivalent 240 V, 0.8 A, 80 W 80 V, 5.1 A, 220 w resistance in per unit. 2. The results of open-circuit and short-circuit tests on a 25-kVA, 440-V/220-V, 60-Hz transformer are as follows: Open-circuit test. Primary open-circuited, with instrumentation on the low- voltage side. Input voltage, 220 V; input current, 9.6 A; input power, 710 w. Short-circuit test. Secondary short-circuited, with instrumentation on the high- voltage side. Input voltage, 42 V; input current, 57 A; input power, 1030 W. Obtain the parameters of the exact equivalent circuit (Figure. 2-4), referred to the high voltage side. Assume that R, = a'R: 3. A 110-kVA, 2200-V/ 110-V, 60-Hz transformer has the following circuit constants: R1= 0.22 0, R; = 0.5 mo, X, = 2.00, X2 = 5 m0, Rc = 5.5 ko, and Xm = 1.1 kn. During and X1= a'X2 voltage side one day (24 hours) the transformer has the following load cycle: 4 h on no-load; 8h on % full-load at 0.8 power factor; 8 h on 14 full-load at unity power factor; and ; and 4 h on full-load at unity power factor. Assuming a constant core loss of 1.346 kW. Find the all-day efficiency of the transformer 4. The ohmic values of the circuit parameters of a transformer, having a turns ratio of 5, are R: = 0.5 0; R2 = 0.021 0; X: = 3.2 0; X2 = 0.12 Q; Rc = 350 n, referred to the primary; and Xm= 98 0, referred to the primary. Draw the approximate approximate equivalent circuits of the transformer, referred to (a) the primary and (b) the secondary.. Show the numerical values of the circuit parameters. The circuits are respectively shown in Figure. 2-12(a) and Figure. 2-12(b). The calculations are as follows: (a) R', X', Rc', X'm (b) R", X", R"c. X"m (c) 102s a m AR A (a) (b) Figure. 6.12 Circuits
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Transcribed Image Text:The power output is (75 x103) = (0.79)(75 x 10) W 326 And so (0.79 )(75 x 103 Nmax = = 97.53% (0.79)(75 x 10')+750+750 138 Assessment Task 6 1. A quantity is expressed in per unit if it is divided by a chosen base quantity having the same physical dimension). Suppose that for a 10-kVA, 2400-V/240-V transformer we choose P_(base )=10kW v_[1 base )=2400v v_(2 base )=240V This transformer has the following test data open-circuit test (on low-voltage side): short-circuit test (on high-voltage side): Convert all test data into per-unit values and find the series equivalent 240 V, 0.8 A, 80 W 80 V, 5.1 A, 220 w resistance in per unit. 2. The results of open-circuit and short-circuit tests on a 25-kVA, 440-V/220-V, 60-Hz transformer are as follows: Open-circuit test. Primary open-circuited, with instrumentation on the low- voltage side. Input voltage, 220 V; input current, 9.6 A; input power, 710 w. Short-circuit test. Secondary short-circuited, with instrumentation on the high- voltage side. Input voltage, 42 V; input current, 57 A; input power, 1030 W. Obtain the parameters of the exact equivalent circuit (Figure. 2-4), referred to the high voltage side. Assume that R, = a'R: 3. A 110-kVA, 2200-V/ 110-V, 60-Hz transformer has the following circuit constants: R1= 0.22 0, R; = 0.5 mo, X, = 2.00, X2 = 5 m0, Rc = 5.5 ko, and Xm = 1.1 kn. During and X1= a'X2 voltage side one day (24 hours) the transformer has the following load cycle: 4 h on no-load; 8h on % full-load at 0.8 power factor; 8 h on 14 full-load at unity power factor; and ; and 4 h on full-load at unity power factor. Assuming a constant core loss of 1.346 kW. Find the all-day efficiency of the transformer 4. The ohmic values of the circuit parameters of a transformer, having a turns ratio of 5, are R: = 0.5 0; R2 = 0.021 0; X: = 3.2 0; X2 = 0.12 Q; Rc = 350 n, referred to the primary; and Xm= 98 0, referred to the primary. Draw the approximate approximate equivalent circuits of the transformer, referred to (a) the primary and (b) the secondary.. Show the numerical values of the circuit parameters. The circuits are respectively shown in Figure. 2-12(a) and Figure. 2-12(b). The calculations are as follows: (a) R', X', Rc', X'm (b) R", X", R"c. X"m (c) 102s a m AR A (a) (b) Figure. 6.12 Circuits
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