1. A particle moves along a straight line with a velocity in millimeters per second given by 400 – 16t where t is in seconds. Calculate V = - the total distance travelled in the first 7 seconds. Assume that initially, the particle is at s = 0.
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- A curvilinear motion of a particle is defined by Vx = 40-15t and y=75-3t^2, where Vx is in meters per second, y is in meters and t is in seconds. It is also known that x = 0 when t = 0.(a) Which of the following gives the nearest value of the second value of time “t” when “x” will be equal to 0.(b) Which of the following gives the nearest value of the velocity when x=0 at the second value of time.(c) Which of the following gives the nearest value of the acceleration when x=0 at the second value of time.The position coordinate of a particle which is confined to move along a straight line is given by s = 2t³ - 24t + 6, where s is measured in meters from a convenient origin and t is in seconds. Determine (a) the time required for the particle to reach a velocity of 72 m/s from its initial condition at t = 0Q3: A particle moves along the x- axis according to the equation (x-14-7t+t^2+t^3 ), where (x) in meter and (t) in seconds. At (t=7 sec) Find (a) The position of the particle (b) It's velocity (c) It's .acceleration
- 9. Two identical blocks of are placed on top of a rotating disk with a radius of r. The first block is a distance of r from the pivot point and the second is placed at. If the disk has an angular acceleration of 1.125 rad speed is 10 rad S $2 one of the two blocks slides off when the angular (you can consider this to be time t = 0 s. How much time will pass before the second block slides off the disk too?A particle in an experimental apparatus has a velocity given by v = k₁√√s, where v is in millimeters per second, the positions is millimeters, and the constant k = 0.22 mm ¹/2s¹. If the particle has a velocity vo = 5 mm/s at t = 0, determine the particle position, velocity, and acceleration as functions of time. To check your work, evalutate the time t, the positions, and the acceleration a of the particle when the velocity reaches 21 mm/s. Answers: t = S= i i a = i S mm mm/s²Problem 1. A particle's curvilinear motion is represented by the equation s(t)=20t + 4t - 3t. What is most nearly the particle's initial velocity? (A) 20 m/s (B) 25 m/s (C) 30 m/s (D) 32 m/s
- The coordinates of a particle undergoing plane motion are x = 15- 2t2 y = 15 – 10t + t² meters where t is in seconds. Determine the velocity in 3 seconds. metersThe position of a particle along a straight line is given by s= 1.01³-11.5t² + 25t ft, where t is in seconds. [Select] (a) Determine the position of the particle when t = 8 seconds in feet. [Select] [Select] [Select] (b) Total distance it travels during the 8 second time interval in feet (c) Determine the velocity of the particle when t = 8 seconds in ft/sec. (d) Determine the acceleration of the particle when t = 8 seconds in ft/sec².The velocity of a particle along the s-axis is given by v = 5s3/2 where s is in millimeters and v is in millimeters per second. Determine the acceleration when s is 1.8 millimeters. Answer: a = i mm/s²
- A particle moves along a straight line with a velocity V = 12 - 312 m/s, where t is in seconds. When t = 0 s. the particle is located 10 m to the left of the origin. Which of the following most nearly gives the distance the particle travels from t = O to t = 10 secs? 932 m 922 m 912 m 902 mThe curvilinear motion of a particle is defined by v= 50 16t and y = 100 - 4t2, where v, is in meters per second, y is in meters, and t is in seconds. It is also known that x = 0 when t = 0. Plot the path of the particle and determine its velocity and acceleration when the position y= 0 is reached.9- A particle is moving along a straight line is subjected to deceleration a=(-2³) m/s², where v is in m/s. If it has a velocity = 8 m/s and a position s= 10 m when = 0, determine its velocity and position when t=4s