1. A firecracker is heading due north with speed v when it explodes into two pieces of equal mass. If one piece is traveling due west with speed v, what is the speed and direction of the second piece? Hint: Call the mass of the firecracker m. Draw a north-south-east-west diagram and overlay a coordinate system (pick an x- and y-direction). Write the initial momentum of the firecracker as a vector (include unit vector notation). Once the firecracker splits in half, what is the mass of each piece? Write the momentum of the piece traveling due west as a vector. Set up a conservation of momentum equation (initial momentum of single firecracker = final momentum of each piece added together), where the components of momentum of the second piece are unknown. Split your equation into components in each direction and solve.

Fo s Seco 1. A ball of mass 1 kg strikes a wall at an angle of 60° with the wall with a speed of 8 m/s. It bounces back with the same speed and same angle as shown in the figure. Search V (a) Calculate the x and y components of the initial momentum. Don't forget to check the signs of the components the momentum. Px,i= kg m/s kg m/s Py,i= (b) Calculate the x and y components of the final momentum. Px,f= Vkg m/s kg m/s Py,f= (c) Calculate the change in momentum in the x and y directions. Apx= kg m/s дру= kg m/s (d) Calculate the impulse in the x-y directions. Jx= kg m/s kg m/s X Jy = (e) If the ball is in contact with the wall for 10 ms, calculate the component of the force in the x and y directions. Fx= Fy= Note: This question has 7 attempts VN ✔N 4

A 0.13 kg baseball has a momentum of p = 11 kg*m/s as it is pitched toward home plate. A 4.2 kg bat swings at the baseball with a momentum of 28 kg*m/s and is in contact with the ball for 0.06 s. Assume the batter doesn't follow through like they should but instead the bat is at rest immediately after being in contact with the baseball (like bunting it). a.How much force was on the baseball when the bat was striking it? b.How much work was done on the baseball by the bat?

Two particles of mass m₁ = 1.4 kg and m₂ = 2.6 kg are traveling with velocities v₁ = 4.6 m/s, and v₂ = 2.7 m/s as shown in the figure below. What is the total momentum of this system? Be sure to give the magnitude and direction of the momentum. magnitude kg. m/s direction ° above the x-axis y V/₂ m₂ m1 x

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E6.) A ball experiences a change in momentum of 24 kg-m/s.a. What is the impulse acting on the ball?b. If the time of interaction is 0.15 s, what is the magnitude of the average force acting on the ball? Answer with the correct formula.

You drop a steel ball and a clay ball, both of the same mass, from the same distance. The steel ball strikes the ground and rebounds with almost the same speed. The clay ball strikes the ground and sticks. Assume the collisions occur over roughly the same amount of time. Which ball exerted a greater force on the ground? Select the correct answer with the best explanation. A. The two exert the same force. Since they collide with the same initial momentum, they will exert thesame force.B. The clay ball exerts the greater force. Since it starts with some momentum and ends with no momen- tum, it undergoes a greater change in momentum than the steel ball, which rebounds with the same momentum (no change).C. The clay ball exerts the greater force. All of its energy is transferred to the floor, whereas the steelball rebounds with the same kinetic energy, doing no work on the floor.D. The steel ball exerts the greater force. Since it starts with some momentum and it reverses the direction of…

Asteroid X, speeding at 100 m/s towards an equally massive but stationary asteroid Y, collides with a glancing blow. After collision, X is deflected 350 from its original direction while Y travels at 450 to the original direction of X. See the before & after picture of the collision below. Assuming total momentum is conserved, find the speed of each asteroid after collision. a.) V = 58.2 m/s, v = 71.8 m/s b.) v = 58.2 m/s, V = 71.8 m/s

A two dimensional collision between a green and a purple ball, where the purple ball strikes the green. If the data for both objects' velocities (x and y components) versus time are provided, and the mass of the balls are identical, what is a way to determine if the momentum of the system conserved? Explain your methodology. Green ball: vx = 0 m/s from t = 0 s to t = 0.4 s vx = 17.42 m/s from t = 0.5 s to t = 5 s vy = 0 m/s from t = 0 s to t = 0.4 s vy = -8.01 m/s from t = 0.5 s to t = 5 s   Purple ball: vx = 22.3 m/s from t = 0 s to t = 0.4 s vx = 4.878 m/s from t = 0.5 s to t = 5 s vy = 2.6 m/s from t = 0 s to t = 0.4 s vy = 10.61 m/s from t = 0.5 s to t = 5 s

Car 1 is traveling in the +x-direction at 10.0 m/s and Car 2 is stationary. Car 1 collides with, and sticks to, Car 2. Car 1 and Car 2 have masses of 995 kg and 1850 kg, respectively. You may ignore friction and other forces external to the system. a. Using the principle of conservation of momentum, find the velocity (magnitude and direction) of the combined system immediately after this perfectly inelastic collision. b. Find the fractional change in kinetic energy for this collision. In other words, determine