1. a) Construct NFA accepting a language L= a (ae)*or (iou)*. E = {a, e,i, 0,u}2. b) Convert the above NFA to anequivalent DFA by using "TabulationMethod".

Answered: 1. a) Construct NFA accepting a…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Type conversion, type coercion, and nonconverting type casts are all different.
Let the function fun be defined as: int fun(int &k) { k += 4; return 3 * k -1; } Suppose the function fun was used in a program as follows: void main() { int i = 10, j = 10, sum1, sum2; sum1 = (i / 2) + fun(i); sum2 = fun(j)) + ( j / 2); } A. What are the values of sum1 and sum2 if the operands in the expressions are evaluated left to right? B. What are the values of sum1 and sum2 if the operands in the expressions are evaluated right to left?
convert the following c++ code in c #include <iostream>#include <iomanip>using namespace std; class Complex{public:Complex(double r = 0.0, double i = 0.0); // constructorvoid setReal(double real);void setImag(double imag);double getReal();double getImag();Complex operator+(const Complex&)const ; // operator+()Complex operator-(const Complex&)const ; // operator-() /*** read the complex number to an input stream*/friend std::istream & operator >>(std::istream &din, Complex &);/*** Friend function declarations* Output complex number to an output stream, Example 3+4i*/friend std::ostream & operator <<(std::ostream &dout, const Complex&); operator double();private://Declaring variablesdouble real, imaginary;}; //Parameterized constructorComplex::Complex(double r,double i){this->real=r;this->imaginary=i;}//Function implementation which adds two complex numbers by using the operator overloading '+'Complex Complex::operator…
Objective: The objective of this discussion is to be aware of various control structures. Problem Statement: Feel free to answer one of the following questions: 1. Discuss the selection constructs. Give an illustrative example for each one of them. 2. Discuss the repetition constructs. Give an illustrative example for each one of them.
(b) Find all the errors in the C++ code below: class Point { private: int x, y: public: Point(int x = 0, int y = 0); int getX() const; // Getters void setX(int x); // Setters void setY(int y); }; Point:: Point(int x, int y) : x(x), y(y) { } // Using initializer list // Getters int Point::getX() const { return x; } int Point::getY) const { return y; } // Setters void Point::setX(int x) { this->x = x; } void Point::setY(int y) { this->y = y; } // Public Functions void print() const { cout « "(" « x« "," « y « ")" « endl; // Member function overloading '+' operator void Point::operator+(Point rhs) const { return Point(x + rhs.x, y + rhs.y); int main() { Point p1(1, 2), p2(4, 5); // Use overloaded operator Point p3 = p1 + p2; p1.print(); // (1,2) p2.print(); / (4,5) p3.print(); / i5,7) Point p5 = p1 + p2 + p3 + p4; p5.print (); // (15,21) cout<
3
No need for explanation only the answer or what to write please and thank you
Define assignment operator.
78
TressetteYou are given the types: type colore = Spade | Coppa | Bastoni | Denari ;; type valore = Ace | Two | Three | Four | Five | Six |Seven | Jack | Knight | King ;; type mazzo = Null | Carta of carta and carta ={ c : colore ; v: valore ; mutable tl : mazzo };; (see the picture with cards) a. Write a function points : mazzo -> int = that given a deck of cards calculates its point score. The scoring is as follows: Ace is worth 1 point; Two, Three, King, Knight, Jack are each worth 1 3 ; and the rest do not contribute the the point total. The total point score is equal to the sum of the individual points, rounded down at the end. b. Write a function max_cards : mazzo -> mazzo = that takes a deck of cards and filters out everything except the greatest cards by value (valore) of each color. The order of cards by value is as follows: Three > Two > Ace > King > Knight > Jack > Seven > Six > Five > Four. Due to the size of the output, lists like…

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1. a) Construct NFA accepting a language L = a (ae)*or (iou)*. Z = {a, e,i, o,u} 2. b) Convert the above NFA to an equivalent DFA by using "Tabulation %3D Method".

1. a) Construct NFA accepting a language L = a (ae)or (iou). Z = {a, e,i, o,u} 2. b) Convert the above NFA to an equivalent DFA by using "Tabulation %3D Method".