1. A 500 V, 250 kW, long shunt compound generator induces an e.m.f. of 480 V when running at 1000 r.p.m. no load. On full load the spped of the machine drops to 975 r.p.m. the flux increases by 15% and the terminal voltage rises to 500 V. If the series and shunt field resistances are 0.02 ohm and 100 ohms respectively, calculate the armature resistance. Assume a voltage drop of 1V per brush. 2. A 250 V shunt generator has a full load armature current of 40 A, under these conditions the losses are: FW= 200 watts, shunt field = 100 watts, core = 260 watts, brush contact = 120 watts, armature copper = 400 watts. For operation at maximum efficiency, when the constant losses are equal to those losses that vary as the square of the load, calculate the maximum efficiency. 3. A series generator having a combined armature and field resistance of 0.4 ohm us running at 1000 rpm and delivering 5.5 kW at a terminal voltage of 110 V. If the speed is raised to 1500 rpm and load adjusted to 10 kW, find the new terminal voltage. Assume the machine is working on straight line portion of magnetization characteristics. 4. The dc shunt generator is connected to a load that draws 28,800 watts, given the armature and shunt field resistance of 0.04 ohm and 48 ohms respectively. If the power delivered in the armature is 106.3% of the power delivered to the load. Calculate the generated e.m.f. of the generator. 5. URS Electrician has a 25 kW series generator used in street lighting has an efficiency of 85 8 when operating at rated load. If the stray power loss is 20 % of the full load loss, calculate the efficiency of the generator when delivering a load of 15 kW, assuming that the stray power loss is substantially constant and the other losses vary as the square of the load.

Introductory Circuit Analysis (13th Edition)
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1. A 500 V, 250 kW, long shunt compound generator induces an e.m.f. of 480 V when
running at 1000 r.p.m. no load. On full load the spped of the machine drops to 975
r.p.m. the flux increases by 15% and the terminal voltage rises to 500 V. If the
series and shunt field resistances are 0.02 ohm and 100 ohms respectively,
calculate the armature resistance. Assume a voltage drop of 1V per brush.
2. A 250 V shunt generator has a full load armature current of 40 A, under these
conditions the losses are: FW = 200 watts, shunt field = 100 watts, core = 260
watts, brush contact = 120 watts, armature copper = 400 watts. For operation at
maximum efficiency, when the constant losses are equal to those losses that vary
as the square of the load, calculate the maximum efficiency.
3. A series generator having a combined armature and field resistance of 0.4 ohm us
running at 1000 rpm and delivering 5.5 kW at a terminal voltage of 110 V. If the
speed is raised to 1500 rpm and load adjusted to 10 kW, find the new terminal
voltage. Assume the machine is working on straight line portion of magnetization
characteristics.
4. The dc shunt generator is connected to a load that draws 28,800 watts, given
the armature and shunt field resistance of 0.04 ohm and 48 ohms respectively.
If the power delivered in the armature is 106.3% of the power delivered to the
load. Calculate the generated e.m.f. of the generator.
5. URS Electrician has a 25 kW series generator used in street lighting has an
efficiency of 85 8 when operating at rated load. If the stray power loss is 20 %
of the full load loss, calculate the efficiency of the generator when delivering a
load of 15 kW, assuming that the stray power loss is substantially constant and
the other losses vary as the square of the load.
Transcribed Image Text:1. A 500 V, 250 kW, long shunt compound generator induces an e.m.f. of 480 V when running at 1000 r.p.m. no load. On full load the spped of the machine drops to 975 r.p.m. the flux increases by 15% and the terminal voltage rises to 500 V. If the series and shunt field resistances are 0.02 ohm and 100 ohms respectively, calculate the armature resistance. Assume a voltage drop of 1V per brush. 2. A 250 V shunt generator has a full load armature current of 40 A, under these conditions the losses are: FW = 200 watts, shunt field = 100 watts, core = 260 watts, brush contact = 120 watts, armature copper = 400 watts. For operation at maximum efficiency, when the constant losses are equal to those losses that vary as the square of the load, calculate the maximum efficiency. 3. A series generator having a combined armature and field resistance of 0.4 ohm us running at 1000 rpm and delivering 5.5 kW at a terminal voltage of 110 V. If the speed is raised to 1500 rpm and load adjusted to 10 kW, find the new terminal voltage. Assume the machine is working on straight line portion of magnetization characteristics. 4. The dc shunt generator is connected to a load that draws 28,800 watts, given the armature and shunt field resistance of 0.04 ohm and 48 ohms respectively. If the power delivered in the armature is 106.3% of the power delivered to the load. Calculate the generated e.m.f. of the generator. 5. URS Electrician has a 25 kW series generator used in street lighting has an efficiency of 85 8 when operating at rated load. If the stray power loss is 20 % of the full load loss, calculate the efficiency of the generator when delivering a load of 15 kW, assuming that the stray power loss is substantially constant and the other losses vary as the square of the load.
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