1.) (1 Point) A steel tape having a correct length of 981.661 m at 22.215°C was used to measure a base line and the recorded readings gave the total length of X. If the average temperature during the measurement was 18.635°C. Determine the value of X. Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.

1.) (1 Point) A steel tape having a correct length of 981.661 m at 22.215°C was used to measure a base line and the recorded readings gave the total length of X. If the average temperature during the measurement was 18.635°C. Determine the value of X. Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: what is meant by laser scanning?

A: Laser scanning is land surveying method that can accurately measure and collect data from buildings…

Q: -Q2/The distance between two points on an acrial photograph is measured as 2 centimetres. The known…

Q: Determine coordinates of centroid of the following shaded area. y 60 mm 20 mm 60 mm -X- 20 mm

A: Consider the given figure Calculate area of the of these two section A1=60×20=1200 mmA2=60×20=1200…

Q: 4. Why the lines on the graph do not pass through the origin?

A: When any graph line does not pass through the origin, it means that when the input equals…

Q: On a vertical photograph of flat terrain, section corners, which are a nominal 1-mi apart, appear a…

A: Part A :- d= 3.319 in.f= 3.5 in.Part B :-d= 68.14mm, f= 156.4mm

Q: For the following orthographic projection, presented in Third Angle projection: • Draw an isometric…

Q: * aut cad Ray is one of the commands for the drawing list. It is used to draw a ray, using two…

A: Explanation : Ray command in AutoCAD is used to draw rays from a starting point in a perticular…

Q: u) axonometric drawing 161. *The space covered by a drawing in a paper after changing the scale from…

A: Ans is option 2.

Q: Determine the coordinates of the centroid of the shaded area. 10 30 y 1 Answers: x = MI y = i 20 10…

Q: How does Image quality depend on a camera’s resolution?

A: The resolution of a camera refers to the amount of details that can be captured by it which is…

Q: Define Tacheometry.

A: Tacheometry is a term related with surveying. Tacheometry is a method through which horizontal…

Q: Discuss the importance of accuracy and precision in surveying measurements

A: In surveying, accuracy, and precision are key ideas that guarantee the dependability and caliber of…

Q: You are a professor of architecture. Show your students where the horizon line and vanishing points…

Q: Give two examples of (a) direct and (b) indirect measurements.

A: Direct measurement is the measurement is performed using the scale of the measuring instrument and…

Q: Determine the x- and y-coordinates of the centroid of the shaded area. Assume a = 50 mm, b = 485 mm,…

A: Given data,fig is givena=50mmb=485mmc=150mmFINDx - and y-coordinates of the centroid of the shaded…

Q: For the following items, answer whether the multiview projection matches the isometric drawing depic…

A: The given figure shows the different items, it is required to state whether the Multiview projection…

Q: Determine the y-coordinate of the centroid of the shaded area as shown in the figure y 60° 60°

A: It is required to determine the y-coordinate of the centroid.

Q: Please make your own question about horizontal and vertical angles (surverying) and solve it on your…

Q: Calculate the y-coordinate of the centroid of the shaded area. 53 mm 22 mm 22 22 mm mm Answer: ỹ : i…

Q: What is the main difference between satellite images and aerial photographs?

A: Difference between satellite images and aerial photographs are mentioned in fallowing table

Q: Among the different methods discussed in measuring horizontal distances (I chose the distance by…

A: The various methods of measuring horizontal distances are as follows: pacing measurement of…

Q: 4. Find the centroid of the shaded area in Figure Scanned by CamScanner 40 mm 27 mm - 20 mm 47 mm- +…

A: Centroid: The point at which the area (or) volume is assumed to be concentrated is known as…

Q: 1. Draw the front view in the direction of F and the top view in the direction T of the given…

A: As in problem it is given that the front view and too view has to be drawn using 1st angle…

Q: Problems 1 and 2. Locate the centroid of the shaded area y =r = 100 mm 100 mm 140 mm 50 mm 140 mm 50…

Q: Determine the y-coordinate of the centroid of the shaded area. y h 0.28h $57 V 57° Answer: ỹ = i

Q: List and describe some of the advantages of learning about land surface features from aerial…

A: Aerial photography is defined as the source of taking photograph from a point in the air by a…

Q: Item 1 Part A Determine the horizontal distance between two points A and B whose elevations above…

Concept explainers

Photogrammetry

Photogrammetry is a technology of taking measurements of physical objects present in the environment, using photographs. It includes the process of recording and analyzing a three-dimension image in the two-dimension form. Photogrammetry was invented around 150 years ago in 1851 by Aimé Laussedat, he was also known as the father of photogrammetry, but this method was not in use until 50 years after its invention. This method was first used in Germany by Dr. Albrecht Meydenbauer in 1893 who was the director of the Royal Prussian Photogrammetric institute founded by him.

Question

100%

please answer the question in the picture with complete and accurate solution.

1.) (1 Point) A steel tape having a correct length of 981.661 m at 22.215°C was
used to measure a base line and the recorded readings gave the total length of X. If
the average temperature during the measurement was 18.635°C. Determine the
value of X.
Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

2. Determine the standard temperature of the steel tape and the length of the line measured, if it was found out that at 35°C the total error due to temperature occurring was 0.03m while at 45°C the total error due to temperature occurring was 0.10m. Use C= 0.0000116/1°C.
1. Describe the basic principles of dilatometer testing. 2. List the main component in dilatometer instruments ( 3. Derived the formula for coefficient of thermal expansion ( 4. Demonstrate how CTE can be measured from dilatometric curve Part 2: CO4 5. Give short description for each given Figure: ( 1.0- Parent glass Glass-ceramic 0.8 S0.6- 0.4- 0.2- 0.0- 200 400 600 800 Temperature (C) Figure 1: Dilatometric curve of parent glass and glass-ceramic sample 0.008 40Z60A 50Z50A 60Z40A 80Z70A 0.007 0.006 0.005 0.004 0.003 0.002 0.001 200 400 600 800 1000 1200 1400 Temperature (°C) Figure 2: Dilatometric curves for each sintered sample, containing different zircon- alumina weight proportions (%) '7/7P dL/Lo*10-6
a student was asked to make a line 500-m long using a 25 m tape that is of standard length at a temperature of.28 deg. C. If the average temperature is 12 deg. C. What is the required measurement? Assume a = 0.0000116 m/m-deg. C
I need a handwritten solution, Thank you..
A surveying team used a 100m tape which is of standard length at 32°C in measuring a certain distance and found out that the length of tape have different tension were applied as shown. Let K = 0.0000116 m/°C. Length of tape (m) Tension Applied (kg) 99.986 10 99.992 14 100.003 20 a. What tension must be applied to the tape at a temperature of 32°C so that it would be of standard length? b. What tension must be applied to the tape at a temperature of 40.6°C so that it would be of standard length?
X = 081 XX = 81
Please help me ASAP. Please put the answer on the paper. Complete solution. I need the answer after 40 minutes. Rate will be given accordingly. Thank you in advance.Line AB was measured and the result is 745m. It is measured using a 30m tape that is0.005m tooshort. The tape is standardized at 20°C under a 4.5kg pull. During measurement the temperature is30°C under a pull of 9.57kg. What is the true horizontal distance of line AB due to incorrect tape length,temperature, and pull? The cross-sectional area of the tape is 0.05cm2 and E = 2x106 kg/cm2.
A 50-m steel tape standardized at 20° was found to be 50.16 m long. This tape was held horizontal to measure a line from A to B in three segments. The data listed in the following table were recorded. Apply corrections for tape length and temperature change to determine the correct length of the line. The coefficient of thermal expansion and contraction of the tape is 0.000116 /unit length/degree Celsius. Section Measured distance (m) Temperature (C°) 35 I 50.00 II 50.00 37 III 31.215 40
Answer in three decimal places
A steel tape, with a coefficient of linear expansion of 0.0000116/C, is known to be 50 meters long at 30°C. The tape was used to measure a line was found to be 15532.28 meters long when the temperature was 27°C. Determine the following: a. Temperature correction per tape length b. Temperature correction for the measured line c. Correct length of the line
Suppose that a = 3.24 m and b= 1.8 m. (Figure 1). Figure y=x¹/2 b 1 of 1 > X Part A Determine the moment of inertia for the shaded area about the axis. Express your answer to three significant figures and include the appropriate units. Submit 0 ■μÃ xª Xh Value a Provide Feedback A X-10 Units Previous Answers Request Answer W X X Incorrect; Try Again; 23 attempts remaining ? Next >
PLEASE SHOW YOUR COMPLETE SOLUTIONS. KINDLY FIX YOUR HANDWRITING. USE PROPER FORMULAS, DON'T DO SHORTCUTS. THANK YOU IN ADVANCE!