Introductory Chemistry: An Active Learning Approach
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Transcribed Image Text:### Understanding D-Mannose Anomers
**Question 10 of 37**
The Haworth projection of D-mannose is shown below.
**Which anomer is depicted?**
#### Haworth Projection Diagram
A cyclic structure of D-mannose is depicted in Haworth projection. The carbon atoms in the ring are numbered clockwise from the anomeric carbon (1) to the end of the ring at carbon (5). The CH2OH group is attached to carbon (5). The OH groups are arranged as follows:
- Carbon 1 (anomeric carbon) has an OH group down.
- Carbon 2 has an OH group up.
- Carbon 3 has an OH group down.
- Carbon 4 has an OH group down.
The molecule represented is β-D-mannose because the OH group on the anomeric carbon (Carbon 1) is oriented downward in the Haworth projection.
**Possible Anomer Options:**
- A) alpha
- B) beta
- C) gamma
- D) delta
The correct answer is **B) beta**.
**Note:** The alpha and beta anomers differ in the position of the OH group attached to the anomeric carbon (carbon 1). In the alpha anomer, the OH group is on the opposite side (down) compared to the CH2OH group attached to carbon 5. In the beta anomer, the OH group is on the same side (up).
This distinction is crucial in carbohydrate chemistry, influencing the stereochemistry and biochemical properties of sugars.
Transcribed Image Text:**Question 11 of 37**
The Haworth projection of D-altrose is shown.
Which carbon is the anomeric carbon?
*Image description:*
The image shows the Haworth projection of D-altrose, a cyclic structure depicted with carbon atoms numbered from 1 to 6. The structure is hexagonal with a ring of oxygen at the top right connecting Carbon 1 (C1) and Carbon 5 (C5). The following groups are attached on each carbon:
- Carbon 1 (anomeric carbon): — OH
- Carbon 2: — OH
- Carbon 3: — OH
- Carbon 4: — OH
- Carbon 5: — CH2OH
- Carbon 6: — OH (pointing upwards)
Each carbon atom is part of the ring and contributes to the hexagonal arrangement.
**Options:**
A) 1
B) 2
C) 3
D) 4
E) 5
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