1= S in. A B C ww k = 250 lb/in. r=3 in. = 400 lb

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A:

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A:

Q: Explain with Sketch: (a) Anchor cable marking. (b)Bitter end of the anchor chain.

A: (a) Anchor cable marking. (b)Bitter end of the anchor chain. Here the explanation with diagram of…

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A:

Q: E material has inner m'K, the temperatu

A:

Q: Mechanical advantage is the ratio of effort to load. a) True b) False

A: Mechanical advantage is the ratio of effort to load. a) True b) False

Q: 60 Ib 90 lb 30 45 150 lb

A: GIVEN DATA- A 150lb BOX GIVEN ACTED BY TWO FORCES WE HAVE TO FIND ACCELERATION OF IT

Q: 3. The joule unit can be converted to which of the following? (A) kg m/s (B) kg m/s (C) Pa m (D)…

A: To select the correct options.

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A:

Q: A 'B 2 ft I 4 ft H. ft E G F

A:

Q: 300 lb B. Ao 20 in. 48 in.- 15 in.

A: Given dataLoad P = 300lb (vertically downwards)

Q: The mechanical advantage of any pulley system ___ with each additional rope added. A. Decreases…

A: Mechanical advantage is defined s the ratio of force produced by machine to the force applied to it.

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A: Draw the free body diagram of the beam and calculate the reactions: Apply static equilibrium…

Q: The loads which tend to increase the length the body is called

A: There are many types of load by which the length of a body changes.

Q: 5. x(0) and š(0) can be applied to

A: the general governing eqation  for a damped spring mass system mx +cx˙+kx¨=0m = mass of blockc=…

Q: F 1000 lb y 500 lb 45° 30°

A:

Q: 7. Where do the maximum BM óččurs for th 10 KN B A 2M 3M a) -54 kNm b) -92 kNm c) -105 kNm d) – 65…

A: Consider a cantilever beam that has fixed support at A. A transverse uniformly distributed load of…

Q: 50 lb A 3 in. C B D 4 in.- -6 in.-

A:

Q: A hollow steel has an outside diameter of 5in. and it's inside diameter is 4in. What is the…

A: Given data Outside diameter = 5 in Inside diameter = 4 in

Q: Figure 1 of 1 |2P A -2 ft- -2 ft- d 2 in.

A: find the maximum magnitude of load P.

Q: A Rods 55y -35y

A:

Q: 5 kip/ft 15 kip ft 15 kip · ft B- 6 ft 10 ft 6 ft

A: Given figure:

Q: (Suuds - pin shorter. The outer s m. Find stiffness of inn

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Q: The value of stress amplitude (in MPa) i

A: Given, Minimum stress,σmin=200 MPaMaximum stress,σmax=400 MPaFind the value of stress amplitude ?

Q: F = 250 lb - 30°, 45 F2 = 375 lb

A:

Q: 6 kip A C 4 ft F 4 kip 8 kip -3 ft--3 ft --3 ft - --3 ft -

A:

Q: Problems: Determine the reaction -4 in.- 4 in. 40 lb 20 lb 2 in. CO 3 in. 3 in. 30%

A:

Q: 5 kip/ft 15 kip It 15 kip · ft B- 10 ft 6 ft 19-

A: lets take x-x in section BD at distance x

Q: 400 N/m B - 3 m -3 m-

A:

Q: In the Figure 6, the absolute force value in the bar AC is (in kN): Figure 6:

A: Introduction: Absolute force: Absolute force, often known as absolute strength, is the maximum…

Q: Whyar 1 75kum Im D

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Q: - B А The value of toughness is measured the under point Point D to point A B. Zero to point D Point…

A: Dear student, as per the given options there is no correct answer. Please find the explanation…

Q: -r = 100 mm 50 mm -180 mm

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Q: Support reactions: Ax = 0, Ay = 6 kip up, Gy = 6 kip up. Please specify y answer to 1 decimal place…

A: Given data Ax=0 Ay=6kip Gy=6kip

Q: ω3 and ω4 = rad/s ?

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Q: 6 kN/m B A-

A: we can see that variable distriubted load of 6 kN/m is acting for 9m.this variable distributed load…

Q: 6 kip/ft 8 kip AB A 9 ft 4.5 ft 5 ft -

A:

Q: gure |2P Pro A |B -2 ft2 ft - –2 ft d 2 in.

A: For solution refer images.

Q: S00 N (a) 600 N-m (b) 400 N/m -3m -3m (c)

A:

Q: 12. How much wall thickness is there between the counterbore and the sides of the counterweight?

A: T=0.063 Answer

Q: 300, lb 300 lb 800, lb 300, lb 800, lb 9 ft G B C D E F 700 Ib. 700 lb 6 panels e 5 rt/panet

A: GIVEN DATA - Truss Given   We have to find force in given member using method of joint

Q: k2 ww -M,L k

A: given;

Q: 4 3 F OD 1 n E

A:

Q: A stadium roof truss is loaded as shown. Determine the force in members AE, EF, and FJ.

A: Consider the cut section of the truss as shown in the figure below. Let all the forces in the cut…

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A: 1.2125mm

Q: F126KN 180KN 26 -3m 1.5m 48 65° 145KN V165 KN

A: Drawing the system of force as shown below – Let us take point A as an origin of the coordinate…

Q: arried by members 5 kN D. is an equilateral t DGH, DFE, BFI s are perpendiculs

A: Understanding member diagram ∑FY=0  , ⇒FBFSin 30°−5 Cos 30°            FBF=8.66 KN ,

Bending Moment

In general, we can define the bending moment as the reaction induced when a certain amount of load or force is applied to an element which makes it bend.