(1 point) Solve the initial value problem yy' + x = Vx² x² +y with y(1) = -V3. a. To solve this, we should use the substitution U = x^2+y^2 help (formulas) u' = 2x+2yy' help (formulas) Enter derivatives using prime notation (e.g., you dy would enter y' for ). b. After the substitution from the previous part, we obtain the following linear differential equation in x, и, и'. 1/2u'=sqrtu help (equations) c. The solution to the original initial value problem is described by the following equation in x, y. y=+-sqrt(9x+9) help (equations)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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(1 point) Solve the initial value problem
yy' +x =
x² + y with y(1) = -V3.
a. To solve this, we should use the substitution
U =
x^2+y^2
help (formulas)
u' =
2x+2yy'
help (formulas)
Enter derivatives using prime notation (e.g., you
dy
would enter y' for
dx
b. After the substitution from the previous part, we
obtain the following linear differential equation
in x, и, и'.
1/2u'=sqrtu
help
(equations)
c. The solution to the original initial value problem
is described by the following equation in x, y.
y=+-sqrt(9x+9)
help (equations)
Transcribed Image Text:(1 point) Solve the initial value problem yy' +x = x² + y with y(1) = -V3. a. To solve this, we should use the substitution U = x^2+y^2 help (formulas) u' = 2x+2yy' help (formulas) Enter derivatives using prime notation (e.g., you dy would enter y' for dx b. After the substitution from the previous part, we obtain the following linear differential equation in x, и, и'. 1/2u'=sqrtu help (equations) c. The solution to the original initial value problem is described by the following equation in x, y. y=+-sqrt(9x+9) help (equations)
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