1 of 3 + Automatic Zoom A particle has a charge of q = +5.6 μC and is located at the origin. As the drawing shows, an electric field of Ex = +232 N/C exists along the +x axis. A magnetic field also exists, and its x and y components are Bx = +1.5 T and B = +1.2 T. Calculate the force (magnitude and direction) exerted on the particle by each of the three fields when it is (a) stationary, (b) moving along the +x axis at a speed of 345 m/s, and (c) moving along the +z axis at a speed of 345 m/s. +Z Bx +x Ex In this problem you will have 3 answers for each part. The three forces you will calculate are the electric force, x-component of the magnetic force, and y-component of the magnetic force. Make sure to provide the units and direction of the force (Force is a vector so we must always provide units!)

1. A magnetic field has a magnitude of 1.20 x 10 T, and an electric field has a magnitude of 4.70 x 10° N/C. Both fields point in the same direction. A positive 2.5 µC charge moves at a speed of 3.00 x 10° m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. N

QUESTION 1 A particle with a charge of 5.60 is traveling with a velocity of 3000 m/x in the direction when it enfers a region of space with an electric field and a magnetic held. The electric field has a magnitude of 240 N/C and points in a direction that is 25 above the +x-axis, the magnetic field has a magnitude of +1.87 and points out of the page See the attached figure Find the magnitude of the net force acting on this particle when it enters this region of space This is part 1 of 2 for this problem 1 Bo 100 tw QUESTION 2 For the particle in problem 1. find the direction of the net force acting on the particle when it enters the region of space. Your answer needs to be the angle measured from the +y-axis. This is part 2 of 2 for this problem

| Scientists in a laboratory onboard a zero-gravity spaceship setup and measure electric and magnetic fields in an experiment chamber. The scientists measure the magnetic field to point in the positive x-direction given by B = B,î. The scientists then measure the net force acting on a charged particle q moving through this chamber. The net force is measured to be F = -F,î + F2j. The particle is moving along the positive z-axis with a velocity given by i = v,k. What are the x and y components of the electric field as measured by the scientists? Express your answers in terms of q, vo, Ba, F1, and F2, as needed.

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Part 2) A proton moving with a speed 3.84 × 10° m/s through a 2.99 T magnetic field experiences a force of magnitude 1.59 x 10-12 N. (Mass of the proton = 1.673 × 10¬27 kg, charge 1.602 × 10-19 C). What is the angle between the proton's velocity and the magnetic field? Part 3) What is the proton's acceleration? a = m/s?

A charged particle is moving through a B-field and experiences a magnetic force (FR>0). The magnetic force vector is shown below. Choose all the vectors that could represent the B-field. Magnetic force B-field 80° 50° 40° 10° 80 10

An electron moves at 2.70 × 106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.00 × 10-² T. Part A What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? Express your answer with the appropriate units. a = 0 xa Submit HÅ Xb Value 016 X.10n Units X Previous Answers Request Answer ?

A charged particle moving through a magnetic field at right angles to the field with a speed of 27.7 m/s experiences a magnetic force of 2.98 10-4 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 5.14 m/s at an angle of 27.2° relative to the magnetic field.N

Two particles have the same charge (q1=q23D1.6x10-1C) and different masses undergo circular motion in a constant magnetic field (B = 0.40 T) with the same speed of 5x10° m/s. If their circular paths differ in radius by 4.9 cm, what is the difference in the mass of these two particles? m2 ml a. 8.18 x10^(-28) kg O b. 7.11 x10^(-28) kg Oc 6.27 x10^(-28) kg O d. 5.00 x10^(-28) kg O e. 9.21 x10^(-28) kg G-Guard O O