= 1 m %3D -2 = 0.3 m The column BD, Figure 1, is mnade of aluminum and has a circular cross section of 0.1m diameter. The = diameter of pin A is 10 mm. It's required to calculate: (a) Compressive stress in the link BD (b) Change in the length of the link BD, ALBD (take E=70GPA) (c) Shear stress in pin A. (Pin A is subjected to double shear) A 3 = 0.5 m P = 3 kN d = 0.1 m D .. ..

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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= 1 m
%3D
-2 = 0.3 m
The column BD, Figure 1, is mnade
of aluminum and has a circular cross
section of 0.1m diameter. The
= diameter of pin A is 10 mm. It's
required to calculate:
(a) Compressive stress in the link BD
(b) Change in the length of the link
BD, ALBD (take E=70GPA)
(c) Shear stress in pin A. (Pin A is
subjected to double shear)
A
3 = 0.5 m
P = 3 kN
d = 0.1 m
D
.. ..
Transcribed Image Text:= 1 m %3D -2 = 0.3 m The column BD, Figure 1, is mnade of aluminum and has a circular cross section of 0.1m diameter. The = diameter of pin A is 10 mm. It's required to calculate: (a) Compressive stress in the link BD (b) Change in the length of the link BD, ALBD (take E=70GPA) (c) Shear stress in pin A. (Pin A is subjected to double shear) A 3 = 0.5 m P = 3 kN d = 0.1 m D .. ..
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