(1) log (9)+ log, (4) is equal to: B) 2 A) logo (13) (2) Solve the equation In (1) = 2: e²+1 e²+1 A) 2+1 e2-1 B) C) 1-82 (3) The solutions of e2x + ex-6=0 are: A) x = ln(2), In(3) A) (6) Suppose that x = 3 tan 8, then cos 0 = =: √x²-9 A) √√9-x² B) C) √9+x² x dx = C) x = 2,-3 D) x = In (2) (4) Assume f is a differentiable function, f x³ f'(x) dx = A) x³ f(x) - fx¹ f(x) dx B) x = ln(2), In(-3) B)x f(x) + c C) x³ f"(x)-3 f x² f(x) dx (5) Which of the following improper integrals converge: A) x dx B)e-2x dx C) logo (2) B) 4 (9) The derivative of 2 sin (2sin-¹x) In 2 A) √1-x2 2+2e -1 (7) According to the method of partial fractions, C) -1 B) A) -2 -8 4 (8) √3 x²+9 TT -1x C) is: 2sin 1x √1-x² B) D) D) 2+2e 1-e C) D) 6 √x²+9 3x (x-1)(x-2)(x-3) D)3 D) Diverges In 2 (2sin-1x) In √1+x² = D) x³ f(x) - 3 f x² f(x) dx D) In (x) dx (x-1) + B (x-2) + (x-3) the value of B is D) (2 cos-¹x) In 2 √1-x²
(1) log (9)+ log, (4) is equal to: B) 2 A) logo (13) (2) Solve the equation In (1) = 2: e²+1 e²+1 A) 2+1 e2-1 B) C) 1-82 (3) The solutions of e2x + ex-6=0 are: A) x = ln(2), In(3) A) (6) Suppose that x = 3 tan 8, then cos 0 = =: √x²-9 A) √√9-x² B) C) √9+x² x dx = C) x = 2,-3 D) x = In (2) (4) Assume f is a differentiable function, f x³ f'(x) dx = A) x³ f(x) - fx¹ f(x) dx B) x = ln(2), In(-3) B)x f(x) + c C) x³ f"(x)-3 f x² f(x) dx (5) Which of the following improper integrals converge: A) x dx B)e-2x dx C) logo (2) B) 4 (9) The derivative of 2 sin (2sin-¹x) In 2 A) √1-x2 2+2e -1 (7) According to the method of partial fractions, C) -1 B) A) -2 -8 4 (8) √3 x²+9 TT -1x C) is: 2sin 1x √1-x² B) D) D) 2+2e 1-e C) D) 6 √x²+9 3x (x-1)(x-2)(x-3) D)3 D) Diverges In 2 (2sin-1x) In √1+x² = D) x³ f(x) - 3 f x² f(x) dx D) In (x) dx (x-1) + B (x-2) + (x-3) the value of B is D) (2 cos-¹x) In 2 √1-x²
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 17E
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