Please only clean handwriting please ASAP for like 1) Let X (ƒ) = *, where * denotes convolution. Let æ(t) denote the inverse Fourier transform of X (f). Then x(t)equalsOx(t) ==Ox(t) = π(x(t):-1,sin(nt)πtOx(t) = e tu(t)-1,{=1,for t≥ 0for t < 00,for t = 0for t = 0

We need to find out inverse Fourier transform of given signal.

1) Let X (f) =*, where * denotes convolution. Let x(t) denote the inverse Fourier transform of X (f). Then x(t) equals Ox(t) = -1, for t≥ 0 1, for t < 0 ○ x(t) = π(sin(t)) Ox(t)= e tu(t) x(t) = -1, 0, for t 0 for t = 0

1) Let X (f) =, where denotes convolution. Let x(t) denote the inverse Fourier transform of X (f). Then x(t) equals Ox(t) = -1, for t≥ 0 1, for t < 0 ○ x(t) = π(sin(t)) Ox(t)= e tu(t) x(t) = -1, 0, for t 0 for t = 0

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

Please only clean handwriting please ASAP for like

1) Let X (ƒ) = *, where * denotes convolution. Let æ(t) denote the inverse Fourier transform of X (f). Then x(t)
equals
Ox(t) =
=
Ox(t) = π(
x(t):
-1,
sin(nt)
πt
Ox(t) = e tu(t)
-1,
{
=
1,
for t≥ 0
for t < 0
0,
for t = 0
for t = 0

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