Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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Solve for x and sum of possible integers.
**Topic: Solving Quadratic Inequalities**

### Inequality:
\[ 1 < (x-2)^2 < 25 \]

### Explanation:

The inequality \(1 < (x-2)^2 < 25\) is a compound inequality involving a quadratic expression. Here, we need to find the values of \(x\) that satisfy both \(1 < (x-2)^2\) and \((x-2)^2 < 25\) simultaneously.

#### Step-by-step Solution:

**Step 1: Solve \( (x-2)^2 < 25 \)**
1. Take the square root on both sides: 
\[ -5 < x-2 < 5 \]
2. Add 2 to each part of the inequality:
\[ -5 + 2 < x < 5 + 2 \]
\[ -3 < x < 7 \]

**Step 2: Solve \( 1 < (x-2)^2 \)**
1. Take the square root on both sides, noting both positive and negative roots:
\[ 1 < x-2 \quad \text{or} \quad x-2 < -1 \]
2. Solve each part separately:
   - For \(1 < x-2\):
     \[ x > 3 \]
   - For \(x-2 < -1\):
     \[ x < 1 \]

**Step 3: Combine the solutions**
- From \(1 < (x-2)^2 < 25\), we need the intersection of \( -3 < x < 7 \) and \( x > 3 \) or \( x < 1 \).

So, the combined solution is:
\[ -3 < x < 1 \quad \text{or} \quad 3 < x < 7 \]

Thus, the solution set for the inequality \(1 < (x-2)^2 < 25\) is:
\[ -3 < x < 1 \quad \text{or} \quad 3 < x < 7 \]

### Graphical Representation:
To visualize this, plot the solutions on a number line:

1. Draw a number line.
2. Mark and shade the regions between \(-3\) and \(1\) (but not including \(-3\) and \(1\)) and between \(3\) and \(7\) (
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Transcribed Image Text:**Topic: Solving Quadratic Inequalities** ### Inequality: \[ 1 < (x-2)^2 < 25 \] ### Explanation: The inequality \(1 < (x-2)^2 < 25\) is a compound inequality involving a quadratic expression. Here, we need to find the values of \(x\) that satisfy both \(1 < (x-2)^2\) and \((x-2)^2 < 25\) simultaneously. #### Step-by-step Solution: **Step 1: Solve \( (x-2)^2 < 25 \)** 1. Take the square root on both sides: \[ -5 < x-2 < 5 \] 2. Add 2 to each part of the inequality: \[ -5 + 2 < x < 5 + 2 \] \[ -3 < x < 7 \] **Step 2: Solve \( 1 < (x-2)^2 \)** 1. Take the square root on both sides, noting both positive and negative roots: \[ 1 < x-2 \quad \text{or} \quad x-2 < -1 \] 2. Solve each part separately: - For \(1 < x-2\): \[ x > 3 \] - For \(x-2 < -1\): \[ x < 1 \] **Step 3: Combine the solutions** - From \(1 < (x-2)^2 < 25\), we need the intersection of \( -3 < x < 7 \) and \( x > 3 \) or \( x < 1 \). So, the combined solution is: \[ -3 < x < 1 \quad \text{or} \quad 3 < x < 7 \] Thus, the solution set for the inequality \(1 < (x-2)^2 < 25\) is: \[ -3 < x < 1 \quad \text{or} \quad 3 < x < 7 \] ### Graphical Representation: To visualize this, plot the solutions on a number line: 1. Draw a number line. 2. Mark and shade the regions between \(-3\) and \(1\) (but not including \(-3\) and \(1\)) and between \(3\) and \(7\) (
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