•1 L •√1-x² -1 J-√√1-x² 2-x²-y² x² + y² (x² + y²)5/²dzdydx
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- ·S- A B C) 回 D For x 1/2 -dx and using the substitution u=x1/2, the resulting integral takes the form: -du / 4u [4-(2u²) ² -du -du V 4u 4 -duEvaluate the integral by converting to polar coordinates. /8-y? 1 dx dy = V1+x² + y²Evaluate the integral by changing to spherical coordinates. V 16 - x2 32 - x2 - y2 yz dz dy dx x²+ y2 + y2
- Convert this integral from rectangular coordinates to cylindrical coordinates (Do not evaluate the integral) √1-y² xzdzdxdy.Evaluate the integral by changing to cylindrical coordinates. √9-y² LIVSP 9-y2 V r6 x² + y² xz dz dx dyFind the surface area of the portion of the cylinder ya + 2² =9 above tne rectangle in the xy plane. where OEXL2 and -35 ys 3 ........ .. ..... . ....