1) into the data memory at address stored in ($s0). Hint: In this problem, the third byte value in th

Assume a CPU with a fixed 32-bit instruction length has the following instruction format:opcode mode [operand1] [operand2] [operand3]The mode encodes the number of operands and each operand’s mode. For instance, one mode indicates three registers, another indicates two registers and an immediate datum, another indicates a main memory reference, etc. Assume there are 94 instructions and 22 modes. Answer the following.a. One mode indicates three registers. How many registers can be referenced in this mode?b. One mode indicates two registers and an immediate datum in two’s complement. Assuming there are 32 registers, what is the largest immediate datum that can be referenced?c. One mode has a destination register and a source memory address (an unsignednumber). Assuming 16 registers, what is the largest memory reference available?d. One mode has two memory addresses, both using base displacement. In both, the basesare stored in index registers and the displacements are specified in the…

The memory location at address 00002001 contains the memory variable in binary form. What is the data memory variable in hexadecimal form? MEMORY 1110 1011 00002001 1110 1010 00002000 1110 1001 00001999 1110 1000 00001998 1110 0111 00001997 1110 0110 00001996 DATA ADDRESS The data memory variable in hexadecimal form is E7. a. b. The data memory variable in hexadecimal form is EA. The data memory variable in hexadecimal form is EB. C. The data memory variable in hexadecimal form is E9. Od.

10.- Consider the following code and pictureLoop1MOVLW 0x32MOVWF REG2DECFSZ REG2,FGOTO LOOP1 If the system clock frequency is aMHz and each machine cycle consumes 4 cycles of it. Calculate the delay time of the LOOP1 loop. Include the execution difference time of the DECFSZ instruction in the last cycle. Select an answerA) 0.6.sB) 6msC)6usD) 60us

Have a question requiring an answer in assembly language

5. The ending address of a memory of size 1KB is 33FFH, then what is the starting address of the memory.