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Analyze the following code fragment and provide an asymptotic (Θ) bound on the running time as a function of n. You do not need to give a formal proof, but you should justify your answer.
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- Create an application that finds the greatest common divisor of two positive integers entered by the user. Console Greatest Common Divisor Finder Enter first number: 12 Enter second number: 8 Greatest common divisor: 4 Continue? (y/n): y Enter first number: 77 Enter second number: 33 Greatest common divisor: 11 Continue? (y/n): y Enter first number: 441 Enter second number: 252 Greatest common divisor: 63 Continue? (y/n): n Specifications The formula for finding the greatest common divisor of two positive integers x and y must follow the Euclidean algorithm as follows: Subtract x from y repeatedly until y < x. Swap the values of x and y. Repeat steps 1 and 2 until x = 0. y is the greatest common divisor of the two numbers. You can use one loop for step 1 of the algorithm nested within a second loop for step 3. Assume that the user will enter valid integers for both numbers. The application should continue only if the user enters 'y' or 'Y' to continue. Note that if you do…The cateve cede x_m= [0;d b = [4₁2] L = [00;20] D = [3020 51 u U = [0 -1; 0 0 True Fallse Fac bdash = inv (L+D) *b; B = inv (L+D) * (°; For n = 2:44 2 x_m=bdash - B*x_m end for Jok p can be executed in order to apply three iteration of the Gauss-Seidel method, taking the initial approximetticD 20995 babisión P 3x₁ - x₂ = -4 2X1 +502 = 2 44 OR ان انار (0) X₁₁² =0=X₂₁₂²², to approximate the solution of the system 2 اورانMatch the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
- ARGUMENT TWO Valid ☐ Invalid ☐ Some X is Z Some Y is not Z ∴ Some Y is X ARGUMENT THREE Valid ☐ Invalid ☐ All C is G All C is L ∴ All L is G ARGUMENT FOUR Valid ☐ Invalid ☐ No Z is L All O is L ∴ No O is a Z ARGUMENT FIVE Valid ☐ ï Invalid ☐ No B is A Some R is not B ∴ Some R is not A ARGUMENT SIX Valid ☐ ï Invalid ☐ All F is M Some S is M ∴ Some S is FNEXIGO prial 5 - Merge COMP1005A COMP1005-F21 Tutorial 5-B1 N 넷블릭스 ca/d21/le/content/82886/viewContent/2138118/View Hangman Game Write a program called hangman.py that will contain problems 1-4. Problem 1 Write a program called p1.py. Create two global variables, one to store the number of incorrect guesses and a second to store a word (example: koala). Page 1 of 6 Write a function called print hangman () that takes no arguments and prints a hangman corresponding to the number of incorrect guesses (use the global variable). Example: x = 4 # number of incorrect guesses print_hangman () /6< in C language means: One's complement O Logical OR O Logical shift right O Inequality O Logical AND O Two's complement O Exclusive OR O Equability O Logical shift left
- WE 36TE 210 B. to9。(3xース)+logto (3xel}alal。 10Output for Sample Input 1 3+ Copydef square(x): return x * X def halve(x): return x // 2 def twice(f,x): """Apply f to the result of applying f to x >>> twice (square,3) 81 >>> twice (square, 4) 256 >>> twice (halve, 32) 8 >>> twice (halve, 80) 20 *** YOUR CODE HERE ***"
- Question 25 What is the output from the following code? public class Main { public static void main(String args[]) { int arr[] = new int [4]0]; arr[0] = new int [1]; arr[1] = new int [2]; arr[2] = new int [3]; arr[3] = new int [4]; int i, j, k = 0; for (i = 0; i < 4; i++) { for (j = 0; jAn ISBN (International Standard Book Number) is a 10 digit number that is used to identify a book. The first nine digits of the ISBN number are used to represent the Title, Publisher and Group of the book and the last digit is used for checking whether ISBN is correct or not. To uniquely identify a book a 10-digit ISBN number is used. The rightmost digit is checksum digit. This digit is determined from the other 9 digits using condition that 10d, + 9dz + 8dg + + d4o must be a multiple of 11 (where d, denotes the i" digit from the right). The checksum digit d; can be any value from 0 to 10: the ISBN convention is to use the value X to denote 10. Write a C program using pointers that receives a 10- digit ISBN, and computes the checksum, and reports whether the ISBN number is correct or not. Example: 007462542X = 10°0 + 9*0 + 8*7 + 74 + 6*6 + 5*2 + 4*5 + 3"4 + 2*2 + 110 = 176 Since 176 leaves no remainder when divided by 11, hence it is a valid ISBN. Note: When the check digit turns out…ul JAWWAL? 10:53 PM 37% Question 4: Write an algorithm that asks the user to enter an integer number then prints the sum of even digits and the sum of odd digits within the number. Example: if the user enters: 2169 The algorithm should print: The sum of even digits is 8 and sum of odd digits is 10.SEE MORE QUESTIONS