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Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Topic Video
Question
Written Assignment Question 3?
Please solve in details.

Transcribed Image Text:3:23 0 &
A all 11%I
2.2 Inverse of a Matrix.pdf
Theorem 2.2.1:
Let A =
If ad - be +0, then A is invertible and
d -b
ad - be
If ad - be = 0, then A is not invertible.
Note that in Example 3, for A = 0 . ad – bc = 0(1) – 1(0) = 0, so the matrix is not invertible. (We
proved this another way.)
> Note: We have a special name for the expression ad – bc. This is called the determinant of A. The
following definition makes this more precise.
DEFINITION: Determinant of a 2x2 Matrix
Let A = 1 The determinant of A is defined as follows:
det(A) = ad - be.
Example 4:
Find the inverse of the matrix = . if A is invertible.
Solution:
First, we calculate det (A) to make sure matrix A is invertible: det(A) = (3)(6) - (4)(5) = -2, so A is
invertible.
Next, we apply the formula from Theorem 2.2.1, which gives:
A1 =L - -3/2)
Link to Video Solution by Professor Matt Lewis: httns://www.educreations.com/lesson/view/example-2-2-
3-1/32439987/
Example 5:
Find the inverse of the matrix = :
if A is invertible.
Solution:
First, we calculate det (A) to make sure matrix A is invertible:
det(A) = (-2)(8) – (4)(-4) = -16 - (-16) = -16 + 16 = 0, so A is not invertible.
Now try Written Assignment, Question 3:
Find all values of x such that the matrix [,.
-1
.0 ,
48 x- 3
|is not invertible.
IV.
Using A-1 to Solve the Matrix Equation Ax = b
Theorem 2.2.2:
If A is an invertible n xn matrix, then for each b in R", the equation AX = b has the unique solution = A-b.
Idea:
A = 6
A(AR) = A-b
(A'A) = A-b
I = A-5
Example 6:
Consider the linear systems below.
(a)
(b)
(c)
[3x1 + 4x2 = 3
15х, + 6х, 3D 7
(3x, + 4x, = 10
15х, + 6х, — —2
(3x1 + 4x2 = 1
(5х, + 6x, 3
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