1 Example 3Design a simply supported rectangularreinforced beam with tension steel only tocarry a service load of 0.9 kip/ft andservice live load of 2.0 kips/ft. (the deadload does not include the weight of thebeam.) The span is 18 ft. Assume No. 3stirrups. Use f = 4,000 psi and f, =60,000 psiAassakkafBeam Design Examples1 Example 3 (cont'd)AAIn this problem we have to determineh, b, and A, This is called "free design".h =?This problem can solved according toThe outlines of Procedure B presentedearlier. For complete solution for thisproblem, please see Example 2-8 of yourA,=?Eb =?HTextbook.

1 Example 3 Design a simply supported rectangular reinforced beam with tension steel only to carry a service load of 0.9 kip/ft and service live load of 2.0 kips/ft. (the dead load does not include the weight of the beam.) The span is 18 ft. Assume No. 3 stirrups. Use f = 4,000 psi and f, = 60,000 psi %3D

1 Example 3 Design a simply supported rectangular reinforced beam with tension steel only to carry a service load of 0.9 kip/ft and service live load of 2.0 kips/ft. (the dead load does not include the weight of the beam.) The span is 18 ft. Assume No. 3 stirrups. Use f = 4,000 psi and f, = 60,000 psi %3D

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter10: Plate Girders

Section: Chapter Questions

Problem 10.7.8P

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A plate girder cross section consists of two flanges, 11⁄2 inchesx 15 inches, and a 5⁄16-inch 3 66-inch web. A572 Grade 50 steel is used. The span length is 55 feet, the service live load is 2.0 kips/ft, and the dead load is 0.225 kips/ft, including the weight of the girder. Bearing stiffeners are placed at the ends, and intermediate stiffeners are placed at 69-20 and 12,-9,, from each end. Does this girder have enough shear strength? a. Use LRFD. b. Use ASD
DESIGN FOR TENSION ONLY (ACI METHOD fe=21mPa fy=276 MPa trength Design 2015 NSCP use ba 24 TL I SPAN 1: DL= 8 KN LL=12 KW/m L = 4.50m 2: DL= 10x/m LLIG W/m L=450m Ⓒ: DL=10 b/m LL 15/m L=4.70 m (4): DL = 8 KN/ 1 =12xx/m L = 4.60m TL IT
A built up section of A992 steel, F, = 345 mPa is %3D made from plates fully welded together. The flanges consist of PL16×380 and PL12×500 for the web. Use the NSCP 2015 specifications. PL16×380 W̟ = 1.5wp A Wu = 3.6wp 10m Which of the following best gives the maximum service dead load, wp? O 40.2 kN/m 26.8 kN/m O 10.8 kN/m O 96.6 kN/m B. PL12x500
A built up section of A992 steel, F, = 345 mPa is made from plates fully welded together. The flanges consist of PL16X380 and PL12X500 for the web. Use the NSCP 2015 specifications. PL16x380 WL = 1.5wp %3D A Wu = 3.6wp 10m Which of the following best gives the maximum service dead load, wp? 40.2 kN/m 26.8 kN/m O 10.8 kN/m O 96.6 kN/m PL12x500
An 80-foot long plate girder (see below) is fabricated from a ½-inch x 78-inch web and two 3inch x 22-inch flanges. Continuous lateral support is provided. The steel is A992. The loading consists of a uniform service dead load of 1.0 kip/ft (including the self-weight), a uniform service live load of 2.0 kips/ft, and a concentrated service live load of 500 kips at midspan. Stiffeners are placed at each end and at 4 feet, 16 feet, and 28 feet from each end. Once stiffener is placed at midspan. Determine whether the flexural strength is adequate using LRFD.
1. Check the beam shown for compliance with the AISCS. Lateral support is provided only at the ends, and A992 steel (E 345 MPa and Fy= 450 MPa). The only uniform service dead load is the weight of the beam. The 70 KN service loads are 30%DL and 70%LL. Use LRFD. 70 KN 70, KN 70 KN W 14 x 68 0.90m 1.20m 0.90m WI4 x68 IR, R2
1%9. l. In. • f 10 Y:- quiz2.pdf > Quiz: Design the reinforcement steel that necessary for the shcar and torsion for the rectangular cantilever beam shown in figure. Use for stirrups (o12) and let f.=25 MPa, f-400 MPa, dead load (5 kN/m?) and live load (10 kN/m), take into account the self-weight of beam. All dimensions in (mm) 1000 800 3000 300 Cnand TEXTEDT II
4/47 Compute the force in member HN of the loaded truss. BE 2 m A 4/40 n L L D R Q L L F 6 m L P O N -8 panels at 3 m Problem 4/47 age to L BODJEN H M L I L L 2- J [2 m EM K
1. Check the beam shown for compliance with the AISCS. Lateral support is provided only at the ends, and A992 steel (E345 MPa and Fu= 450 MPa). The only uniform service dead load is the weight of the beam. The 70 KN service loads are 30%DL and 70%LL. Use LRFD. IR₁ 0.90m 70,KN * W14 x 68 1.20m 70 KN * 0.90m R₂ W14x68 70 KN
Design a rectangular beam to carry a live load of 1.5 kips/ft and a dead load of 1.5 kips/ft inn addition to the beam weight for a simple span of 32 ft use an approximate steel ratio P of about 0.375 of the balanced amount and also satisfy aci table 9.5 use fc' 4000 psi fy 40.000 psi and dy=60.000 psi
USE NSCP 2010 A rectangular beam reinforced for both tension and compression barshas an area of 1450 mm² for compression bars and 4350 mm² fortension bars. The tension bars and compression bars are placed at a distance of 600 mm and 62.5 mm respectively from the top of thebeam. The beam width 300 mm, fc’ = 21 MPa, fy = 415 MPa andtension steel covering is 60 mm.If it is 8 m-simply-supported beam that carries three concentratedservice live loads P applied at three quarter points of the beam (exceptat the supports), neglecting the self weight of the beam, determine themaximum value of service load P in kiloNewtons.
5.5-3 A simplrted beam is subjected to a uniform service dead load of 1.0 kip cluding the weight of the beam), a uniform service live load of 0 kipft, and a concentrated service dead load of 40 kips. The beam feet long, and the concentrated load is located 15 feet from the left The beam has continuous lateral support, and A572 Grade 50 steel is used. Is a W30 x 108 adequate a. Use LRFD. b. Use ASD.