Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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- Let f(x) = 2³ – 18x2 – 240x. Complete this problem without a graphing calculator. (a) The derivative of f(x) is f'(x) = (b) As a comma-separated list, the critical points of f are x = Since f is continuous on the closed interval [-5, 18], f has both an absolute maximum and an absolute minimum on the interval [-5, 18] according to the Extreme Value Theorem. To find the extreme values, we evaluate f at the endpoints and at the critical points. (c) As a comma-separated list, the y-values corresponding to the critical points and endpoints are y = (d) The minimum value of f on [-5, 18] is y = the minimum value occurs at x = and this x is a(n) ? (e) The maximum value of f on [-5, 18] is y = the maximum value occurs at = and this x is a(n) ?arrow_forwardLet f(x) = |3 – x²|] Estimate f'(1)d (Hint: h = 0.0001)arrow_forwardx²- 2x-8 if x+4 (4) F (x)=, х-4 • if f is continuous at x=4, а, if x = 4 then a =.arrow_forward
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