(1-cos(x))= (2-2sin^2(x)) from (-pi, pi)

DERIVATIVE OF (cosx/1+sinx)^5

* Subscribe An object is thrown in the air with vertical velocity of 20 ft/s and horizontal velocity of 15 ft/s. The object's height can be described by the equation y (t) = -162+20t while the object moves horizontally with constant velocity 15 ft/s. Write parametric equations for the object's position, and then eliminate time to write height as a function of horizontal position. How did you arrive at your conclusion(s) for this problem? *Provide your initial post, read posts from your classmates, and contribute to the discussion by responding (with a minimum of 3 sentences). You may collaborate together to complete the solution. Your response should be well thought out and further the discussion. Use the graphical equation editor when necessary to express your answer. Rubrics E Discussion Rubric

(sin x +cos x)^2 =1+sin x cos x

Evaluate each of the following: 1. ln(-e) 2. i^i 3. cos(i*ln(-1)) 4. cosh^-1(-1)

First Derivative of: (tan3(2x)) / x1/5 + ln(7x+4)   Do not need to simplify