Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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### Problem 1: Solution pH Calculation

**Objective:** Calculate the pH of a solution prepared by dissolving 1.90 g of sodium acetate, \( \text{CH}_3\text{COONa} \), in 85.0 mL of 0.20 M acetic acid, \( \text{CH}_3\text{COOH (aq)} \). Assume the volume change upon dissolving the sodium acetate is negligible. The \( K_a \) of \( \text{CH}_3\text{COOH} \) is \( 1.75 \times 10^{-5} \).

**Given Data:**
- Mass of sodium acetate (\( \text{CH}_3\text{COONa} \)): 1.90 g
- Volume of acetic acid solution: 85.0 mL
- Molarity of acetic acid solution: 0.20 M
- \( K_a \) of acetic acid: \( 1.75 \times 10^{-5} \)

**Steps to Calculate pH:**

1. **Convert mass of sodium acetate to moles:**
   - Molar mass of \( \text{CH}_3\text{COONa} \): 82.03 g/mol
   \[
   \text{Moles of } \text{CH}_3\text{COONa} = \frac{1.90 \text{ g}}{82.03 \text{ g/mol}} = 0.02316 \text{ moles}
   \]

2. **Convert volume of acetic acid solution from mL to L:**
   \[
   \text{Volume (L)} = 85.0 \text{ mL} \times \frac{1 \text{ L}}{1000 \text{ mL}} = 0.085 \text{ L}
   \]

3. **Calculate the initial concentration of acetic acid:**
   \[
   [\text{CH}_3\text{COOH}]_0 = 0.20 \text{ M}
   \]

4. **Calculate the concentration of sodium acetate:**
   \[
   [\text{CH}_3\text{COONa}] = \frac{0.02316 \text{ moles}}{0.085 \text{
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Transcribed Image Text:### Problem 1: Solution pH Calculation **Objective:** Calculate the pH of a solution prepared by dissolving 1.90 g of sodium acetate, \( \text{CH}_3\text{COONa} \), in 85.0 mL of 0.20 M acetic acid, \( \text{CH}_3\text{COOH (aq)} \). Assume the volume change upon dissolving the sodium acetate is negligible. The \( K_a \) of \( \text{CH}_3\text{COOH} \) is \( 1.75 \times 10^{-5} \). **Given Data:** - Mass of sodium acetate (\( \text{CH}_3\text{COONa} \)): 1.90 g - Volume of acetic acid solution: 85.0 mL - Molarity of acetic acid solution: 0.20 M - \( K_a \) of acetic acid: \( 1.75 \times 10^{-5} \) **Steps to Calculate pH:** 1. **Convert mass of sodium acetate to moles:** - Molar mass of \( \text{CH}_3\text{COONa} \): 82.03 g/mol \[ \text{Moles of } \text{CH}_3\text{COONa} = \frac{1.90 \text{ g}}{82.03 \text{ g/mol}} = 0.02316 \text{ moles} \] 2. **Convert volume of acetic acid solution from mL to L:** \[ \text{Volume (L)} = 85.0 \text{ mL} \times \frac{1 \text{ L}}{1000 \text{ mL}} = 0.085 \text{ L} \] 3. **Calculate the initial concentration of acetic acid:** \[ [\text{CH}_3\text{COOH}]_0 = 0.20 \text{ M} \] 4. **Calculate the concentration of sodium acetate:** \[ [\text{CH}_3\text{COONa}] = \frac{0.02316 \text{ moles}}{0.085 \text{
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